Question : If $AD, BE$ and $CF$ are medians of $\triangle ABC$, then which of the following statement is correct?

Option 1: $(AD + BE + CF) > (AB + BC + CA)$

Option 2: $(AD + BE + CF) < (AB + BC + CA)$

Option 3: $(AD + BE + CF ) =  (AB + BC + CA)$

Option 4: $(AD + BE + CF ) = \sqrt2(AB+BC+CA)$

Question : In a triangle ABC, AD, BE, and CF are three medians. The perimeter of ABC is:

Option 1: equal to $(\overline {AD}+\overline{BE}+\overline{CF})$

Option 2: greater than $(\overline {AD}+\overline{BE}+\overline{CF})$

Option 3: less than $(\overline {AD}+\overline{BE}+\overline{CF})$

Option 4: none of these

Question : In a $\triangle ABC$, the median AD, BE, and CF meet at G, then which of the following is true?

Option 1: 4(AD + BE + CF) > 3(AB + BC + AC)

Option 2: 2(AD + BE + CF) > (AB + BC + AC)

Option 3: 3(AD + BE + CF) > 4(AB + BC + AC)

Option 4: AB + BC + AC > AD + BE + CF

Question : In a $\triangle ABC$, AD, BE and CF are the medians from vertices A, B, and C, respectively. The point of intersection of AD, BE and CF is called

Option 1: median point

Option 2: orthocentre

Option 3: centroid

Option 4: incentre