Question : If $\sec x + \tan x = 5$ and $cosec\; y - \cot y = \frac{1}{3}$, then find the value of $(\sec x + cosec \;y) -(\tan x - \cot y)$.
Option 1: 4.2
Option 2: 3.2
Option 3: 2.2
Option 4: 3.1
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Correct Answer: 3.2
Solution : $\sec x + \tan x = 5$ $\sec^2x - \tan^2x = 1$ $⇒ (\sec x + \tan x)(\sec x - \tan x) = 1$ $⇒ 5 \times (\sec x - \tan x) = 1$ $⇒ (\sec x - \tan x) = \frac{1}{5}$ Now, $\operatorname{cosec}y - \cot y =\frac{1}{3}$ $\operatorname{cosec}^2y - \cot^2y = 1$ $⇒(\operatorname{cosec}y + \cot y)(\operatorname{cosec}y - \cot y) = 1$ $⇒ \frac{1}{3} \times (\operatorname{cosec} y + \cot y) = 1$ $⇒ \operatorname{cosec} y + \cot y = 3$ Again according to the question, $(\sec x + \operatorname{cosec} y) - (\tan x - \cot y)$ $= \sec x + \operatorname{cosec} y - \tan x + \cot y$ $= \sec x - \tan x + \operatorname{cosec}y + \cot y$ $= \frac{1}{5} + 3 = 3.2$ ∴ The value of $(\sec x + cosec \;y) -(\tan x - \cot y)$ is 3.2. Hence, the correct answer is 3.2.
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Question : If $\frac{x-x\tan^{2}30^{\circ}}{1+\tan^{2}30^{\circ}}=\sin^{2}30^{\circ}+4\cot^{2}45^{\circ}-\sec^{2}60^{\circ}$, then value of $x$ is:
Option 1: $\frac{1}{4}$
Option 2: $\frac{1}{5}$
Option 3: $\frac{1}{2}$
Option 4: $\frac{1}{\sqrt3}$
Question : If $\sec \beta+\tan \beta=2$, then what is the value of $\cot \beta$?
Option 1: $\frac{5}{3}$
Option 2: $\frac{3}{5}$
Option 3: $\frac{4}{3}$
Option 4: $\frac{3}{4}$
Question : If $6 \sec \theta=10$, then find the value of $\frac{5 \operatorname{cosec} \theta-3 \cot \theta}{4 \cos \theta+3 \sin \theta}$.
Option 1: $\frac{2}{3}$
Option 2: $\frac{3}{2}$
Option 3: $\frac{5}{6}$
Option 4: $\frac{6}{5}$
Question : What is the value of $\frac{1+\tan A}{\operatorname{cosec} A}+\frac{1+\cot A}{\sec A}$?
Option 1: $2\sec^2A$
Option 2: $\sec \mathrm{A} - \mathrm{cosec A}$
Option 3: $\sec \mathrm{A} + \mathrm{cosec A}$
Option 4: $2 \;\mathrm{cosec^2 A}$
Question : If $X$ is 20% less than $Y$, then find the values of$\frac{Y–X}{Y}$ and $\frac{X}{X–Y}$.
Option 1: $\frac{1}{5}$ and $-4$
Option 2: $5$ and $-\frac{1}{4}$
Option 3: $\frac{2}{5}$ and $-\frac{5}{2}$
Option 4: $\frac{3}{5}$ and $-\frac{5}{3}$
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