Question : If $0\leq \theta\leq \frac{\pi}{2}$ and $\sec^{2}\theta+\tan^{2}\theta=7$, then $\theta$ is:
Option 1: $\frac{5\pi}{12}$
Option 2: $\frac{\pi}{3}$
Option 3: $\frac{\pi}{5}$
Option 4: $\frac{\pi}{6}$
Correct Answer: $\frac{\pi}{3}$
Solution : Given: $\sec^{2}\theta+\tan^{2}\theta=7$ -------------(1) We know that $\sec^{2}\theta-\tan^{2}\theta=1$ ------------(2) Adding equations (1) and (2), we have, ⇒ $2\sec^{2}\theta=8$ ⇒ $\sec^{2}\theta=4$ ⇒ $\sec\theta=2$ ⇒ $\sec\theta=\sec60°$ ⇒ $\theta=60°=\frac{\pi}{3}$ Hence, the correct answer is $\frac{\pi}{3}$.
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Question : If $\frac{\tan\theta +\cot\theta }{\tan\theta -\cot\theta }=2, (0\leq \theta \leq 90^{0})$, then the value of $\sin\theta$ is:
Option 1: $\frac{2}{\sqrt3}$
Option 2: $\frac{\sqrt3}{2}$
Option 3: $\frac{1}{2}$
Option 4: $1$
Question : If $\tan (11 \theta)=\cot (7 \theta)$, then what is the value of $\sin ^2(6 \theta)+\sec ^2(9 \theta)+\operatorname{cosec}^2(12 \theta) ?$
Option 1: $\frac{23}{6}$
Option 2: $\frac{35}{12}$
Option 3: $\frac{31}{12}$
Option 4: $\frac{43}{12}$
Question : If $0 \leq \theta \leq 90^{\circ}$ and $\sec ^{107} \theta+\cos ^{107} \theta=2$, then, $(\sec \theta+\cos \theta)$ is equal to:
Option 1: $2$
Option 2: $1$
Option 4: $2^{-107}$
Question : If $0°<\theta<90°$ and $2\sec\theta =3 \operatorname{cosec}^2 \theta$, then $\theta$ is:
Option 1: $\frac{\pi}{6}$
Option 2:
$\frac{\pi}{4}$
Option 3:
$\frac{\pi}{3}$
Option 4:
$\frac{\pi}{5}$
Question : If $\frac{1}{\operatorname{cosec} \theta+1}+\frac{1}{\operatorname{cosec} \theta-1}=2 \sec \theta, 0^{\circ}<\theta<90^{\circ}$, then the value of $\frac{\tan \theta+2 \sec \theta}{\operatorname{cosec} \theta}$ is:
Option 1: $\frac{4+\sqrt{2}}{2}$
Option 2: $\frac{2+\sqrt{3}}{2}$
Option 3: $\frac{4+\sqrt{3}}{2}$
Option 4: $\frac{2+\sqrt{2}}{2}$
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