Question : If $x^{2}+y^{2}+z^{2}=14$ and $xy+yz+zx=11$, then the value of $(x+y+z)^{2}$ is:
Option 1: 16
Option 2: 25
Option 3: 36
Option 4: 49
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Correct Answer: 36
Solution : Given: $x^{2}+y^{2}+z^{2}=14$ and $xy+yz+zx=11$ Thus, $(x+y+z)^{2}=x^2+y^2+z^2+2(xy+yz+zx)$ Putting the values, we get $(x+y+z)^{2}=14+2(11)$ ⇒ $(x+y+z)^{2}=14+22$ ⇒ $(x+y+z)^{2}=36$ Hence, the correct answer is 36.
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Question : If $x+y+z = 22$ and $xy+yz+zx = 35$, then what is the value of $\small (x-y)^{2}+(y-z)^{2}+(z-x)^{2}$?
Option 1: 793
Option 2: 681
Option 3: 758
Option 4: 715
Question : $x,y,$ and $z$ are real numbers. If $x^3+y^3+z^3 = 13, x+y+z = 1$ and $xyz=1$, then what is the value of $xy+yz+zx$?
Option 1: –1
Option 2: 1
Option 3: 3
Option 4: –3
Question : If $\frac{x^2}{yz}+\frac{y^2}{zx}+\frac{z^2}{xy}=3$, then what is the value of $(x+y+z)^3$?
Option 1: 0
Option 3: 2
Option 4: 3
Question : If $xy+yz+zx=1$ , then the value of $\frac{1\:+\:y^2}{(x\:+\:y)(y\:+\:z)}$ is:
Option 1: 2
Option 2: 3
Option 3: 4
Option 4: 1
Question : If $x+y+z=0$, then the value of $\frac{x^2}{yz}+\frac{y^2}{zx}+\frac{z^2}{xy}$ is:
Option 1: 3
Option 3: 0
Option 4: 2
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