Question : If $a=26$ and $b=22$, then the value of $\frac{a^3-b^3}{a^2-b^2}-\frac{3 a b}{a+b}$ is_______.
Option 1: $\frac{5}{3}$
Option 2: $\frac{13}{11}$
Option 3: $\frac{1}{3}$
Option 4: $\frac{11}{13}$
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Correct Answer: $\frac{1}{3}$
Solution : Given, $a=26$ and $b=22$ Now, $\frac{a^3-b^3}{a^2-b^2}-\frac{3ab}{a+b}$ = $\frac{(a-b)(a^2+b^2-ab)}{(a-b)(a+b)}-\frac{3ab}{a+b}$ = $\frac{a^2+b^2-2ab}{a+b}$ = $\frac{(a-b)^2}{a+b}$ = $\frac{(26-22)^2}{(26+22)}$ = $\frac{4^2}{48}$ = $\frac{1}{3}$ Hence, the correct answer is $\frac{1}{3}$.
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Question : If $\tan A=\frac{5}{12}$, then the value of $\cos A=$______.
Option 1: $\frac{12}{5}$
Option 2: $\frac{13}{5}$
Option 3: $\frac{5}{13}$
Option 4: $\frac{12}{13}$
Question : If $\frac{11-13x}{x}+\frac{11-13y}{y}+\frac{11-13z}{z}=5$, then what is the value of $\frac{1}{x}+\frac{1}{y}+\frac{1}{z}$?
Option 1: $1$
Option 3: $\frac{13}{5}$
Option 4: $4$
Question : If $\cot A=\frac{12}{5}$, then the value of $\sin A=?$
Option 1: $\frac{5}{13}$
Option 2: $\frac{12}{13}$
Option 3: $\frac{5}{12}$
Option 4: $\frac{13}{12}$
Question : Let $x=\frac{5 \frac{3}{4}-\frac{3}{7} \times 15 \frac{3}{4}+2 \frac{2}{35} \div 1 \frac{11}{25}}{\frac{3}{4} \div 5 \frac{1}{4}+5 \frac{3}{5} \div 3 \frac{4}{15}}$. When $y$ is added to $x$, the result is $\frac{7}{13}$. What is the value of $y$?
Option 1: $\frac{1}{13}$
Option 2: $\frac{9}{13}$
Option 3: $\frac{2}{13}$
Option 4: $\frac{4}{13}$
Question : If $2=x+\frac{1}{1+\frac{1}{5+\frac{1}{2}}}$, then the value of $x$ is equal to:
Option 1: $\frac{14}{13}$
Option 2: 1
Option 3: $\frac{13}{15}$
Option 4: $\frac{15}{13}$
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