Question : If $a-b=1$ and $a^{3}-b^{3}=61$, then the value of $ab$ will be:
Option 1: –20
Option 2: 20
Option 3: 30
Option 4: 60
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Correct Answer: 20
Solution : Given: $a-b=1$ and $a^{3}-b^{3}=61$ $\therefore a^3–b^3=(a–b)^3+3ab(a–b)$ Putting the values, we get ⇒ $61 = 1 + 3ab × 1$ ⇒ $61 – 1 = 3ab$ ⇒ $3ab= 60$ Thus, $ab=\frac{60}{3}=20$ Hence, the correct answer is 20.
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Question : If $a - b = 2$ and $a^3 - b^3 = 80$, then what will be the value of $ab$?
Option 1: 12
Option 2: –24
Option 3: 24
Option 4: –12
Question : If $9x^2+16y^2=60$ and $3x+4y=6$, then the value of $xy$ is:
Option 1: –1
Option 2: 1
Option 3: –2
Option 4: 2
Question : If (a – b) = 1 and ab = 6, then what is the value of (a3 – b3)?
Option 1: 21
Option 2: 23
Option 3: 19
Option 4: 25
Question : If $\frac{a}{b}+\frac{b}{a}=1$, then the value of $a^{3}+b^{3}$ will be:
Option 1: 1
Option 2: 0
Option 3: –1
Question : If $a+b=1$, find the value of $a^{3}+b^{3} - ab-(a^{2}-b^{2})^{2}$.
Option 3: 0
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