Question : If $a-b=1$ and $a^{3}-b^{3}=61$, then the value of $ab$ will be:
Option 1: –20
Option 2: 20
Option 3: 30
Option 4: 60
New: SSC CGL 2025 Tier-1 Result
Latest: SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: 20
Solution : Given: $a-b=1$ and $a^{3}-b^{3}=61$ $\therefore a^3–b^3=(a–b)^3+3ab(a–b)$ Putting the values, we get ⇒ $61 = 1 + 3ab × 1$ ⇒ $61 – 1 = 3ab$ ⇒ $3ab= 60$ Thus, $ab=\frac{60}{3}=20$ Hence, the correct answer is 20.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : If $a - b = 2$ and $a^3 - b^3 = 80$, then what will be the value of $ab$?
Option 1: 12
Option 2: –24
Option 3: 24
Option 4: –12
Question : If $9x^2+16y^2=60$ and $3x+4y=6$, then the value of $xy$ is:
Option 1: –1
Option 2: 1
Option 3: –2
Option 4: 2
Question : If $a+b=1$, find the value of $a^{3}+b^{3} - ab-(a^{2}-b^{2})^{2}$.
Option 3: 0
Question : If $\frac{a}{b}+\frac{b}{a}=1$, then the value of $a^{3}+b^{3}$ will be:
Option 1: 1
Option 2: 0
Option 3: –1
Question : If $\text{a}= {\sqrt{2}+1}$ and $\text{b} = {\sqrt{2}–1}$, then the value of $\frac{1}{a+1}+\frac{1}{b+1}$ will be:
Option 1: 0
Option 3: 2
Option 4: –1
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile