Question : If $a=10$ and $b=3$, then what is the value of $\frac{(a+b)^2}{a^2-b^2}$?
Option 1: $\frac{182}{93}$
Option 2: $\frac{169}{91}$
Option 3: $\frac{185}{91}$
Option 4: $\frac{185}{93}$
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Correct Answer: $\frac{169}{91}$
Solution : putting the value $a=10$ and $b=3$, we get, $\frac{(a+b)^2}{a^2-b^2}$ = $\frac{(10+3)^2}{10^2-3^2}$ = $\frac{13^2}{100-9}$ = $\frac{169}{91}$ Hence, the correct answer is $\frac{169}{91}$.
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Question : If cos A = $\frac{5}{13}$, then what is the value of (tan A + cot A)?
Option 1: $\frac{60}{169}$
Option 2: $\frac{109}{169}$
Option 3: $\frac{169}{60}$
Option 4: $\frac{169}{109}$
Question : If $a+\frac{1}{a}=2$ and $b+\frac{1}{b}=-2$, then what is the value of $a^2+\frac{1}{a^2}+b^2+\frac{1}{b^2} ?$
Option 1: 0
Option 2: 2
Option 3: 8
Option 4: 4
Question : If $3x+\frac{1}{5x}=7$, then what is the value of $\frac{5x}{(15x^{2}+15x+1)}?$
Option 1: $\frac{1}{5}$
Option 2: $\frac{1}{10}$
Option 3: $\frac{2}{5}$
Option 4: $10$
Question : If $a^2+\frac{1}{a^2}=\frac{7}{3}$, then what is the value of $\left(a^3-\frac{1}{a^3}\right)?$
Option 1: $\frac{5}{3 \sqrt{3}}$
Option 2: $\frac{10}{3 \sqrt{3}}$
Option 3: $\frac{7}{3 \sqrt{3}}$
Option 4: $\frac{8}{3 \sqrt{3}}$
Question : If $3 \operatorname{cosec} A=7$, then what is the value of $\cos A \tan A$?
Option 1: $\frac{2 \sqrt{10}}{7}$
Option 2: $\frac{3}{7}$
Option 3: $\frac{4}{7}$
Option 4: $\frac{\sqrt{10}}{7}$
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