Question : If $\frac{a^2}{b+c}=\frac{b^2}{c+a}=\frac{c^2}{a+b}=1$, then find the value of $\frac{2}{1+a}+\frac{2}{1+b}+\frac{2}{1+c}$.

Option 1: 0

Option 2: 1

Option 3: 2

Option 4: 3

Question : If $a+b=2c$, then the value of $\frac{a}{a–c}+\frac{c}{b–c}$ is equal to (where $a\neq b\neq c$):

Option 1: $–1$

Option 2: $1$

Option 3: $0$

Option 4: $\frac{1}{2}$

Question : The value of $\frac{p^{2}- (q - r)^{2}}{(p + r)^{2} - (q)^{2}}$ + $\frac{q^{2} - (p - r)^{2}}{(p + q)^{2} - (r)^{2}}$ + $\frac{r^{2}- (p - q)^{2}}{(q + r)^{2} - (p)^{2}}$ is:

Option 1: 1

Option 2: 2

Option 3: 0

Option 4: 3

Question : If $p+q+r=pqr=\frac{1}{p}+\frac{1}{q}+\frac{1}{r}=1$, find $\mathrm{p}^3+\mathrm{q}^3+\mathrm{r}^3$.

Option 1: 1

Option 2: –1

Option 3: 5

Option 4: –5

Question : The value of $ \frac{(p-q)^3+(q-r)^3+(r-p)^3}{12(p-q)(q-r)(r-p)}$, where $p \neq q \neq r$, is equal to:

Option 1: $\frac{1}{9}$

Option 2: $\frac{1}{3}$

Option 3: $\frac{1}{4}$

Option 4: $\frac{1}{2}$