Question : If one root of the equation $Ax^{2}+Bx+C=0$ is two and a half times the others, then which of the following is true?
Option 1: $7B^{2}=3CA$
Option 2: $7B^{2}=4CA$
Option 3: $7B^{2}=36CA$
Option 4: $10B^{2}=49CA$
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Correct Answer: $10B^{2}=49CA$
Solution : $Ax^{2} + Bx + C = 0$ Let one root be $p$ and then the other root will be $2.5p$. $⇒ p+2.5p=-\frac{B}{A}$ (sum of the roots) $⇒ 3.5p=-\frac{B}{A}$......(i) Also, $p\times2.5p=\frac{C}{A}$ (product of the roots) $⇒ 2.5p^{2}=\frac{C}{A}$........(ii) From equation (i) and (ii) $\frac{2.5 \times B^{2}}{(3.5\times3.5\times A^{2})} =\frac{C}{A}$ $⇒ B^{2} = 4.9CA$ $⇒10B^{2} = 49CA$ Hence, the correct answer is $10B^{2} = 49CA$.
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Question : If $a^{2}=by+cz$, $b^{2}=cz+ax$, $c^{2}=ax+by$, then the value of $\frac{x}{a+x}+\frac{y}{b+y}+\frac{z}{c+z}$ is:
Option 1: $1$
Option 2: $a+b+c$
Option 3: $\frac{1}{a}+\frac{1}{b}+\frac{1}{c}$
Option 4: $0$
Question : If $ax+by=1$ and $bx+ay=\frac{2ab}{a^{2}+b^{2}}$, then $(x^{2}+y^{2})(a^{2}+b^{2})$ is equal to:
Option 1: 1
Option 2: 2
Option 3: 0.5
Option 4: 0
Question : If the sum of the roots of a quadratic equation is 1 and the product of the roots is –20, find the quadratic equation.
Option 1: $x^{2}–x–20=0$
Option 2: $x^{2}+x+20=0$
Option 3: $x^{2}+x–20=0$
Option 4: $x^{2}–x+20=0$
Question : What is the value of ${a}^3+{b}^3+{c}^3$ if $(a+b+c)=0$?
Option 1: $a^2+b^2+c^2-3abc$
Option 2: $0$
Option 3: $3abc$
Option 4: $a^2+b^2+c^2-ab-bc-ca$
Question : The value of $x$ which satisfies the equation $\frac{x \:+\: a^2 \:+\: 2c^2}{b \:+\: c} + \frac{x \:+\: b^2 \:+\: 2a^2}{c+a} + \frac{x \:+\: c^2 \:+\: 2b^2}{a \:+\: b} = 0$ is:
Option 1: $(a^2+b^2+c^2)$
Option 2: $- (a^2+b^2+c^2)$
Option 3: $(a^2+2b^2+c^2)$
Option 4: $-(a^2+b^2+2c^2)$
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