Hello. So this is considered as,

"p implies negation p and negation q " should be false  precisely p=> (~p^~q) =false

First rule of implication, a true statement cannot imply a false statement. If this is the case end result is false. So lhs value should be true that is p value should be true and entire rhs value is false

so p values is true

Coming to rhs , it should be false.

Since p value is true, negation p is false. (False ^~q) Is false

Rule of and implies, if both are false then end result is false or both are true end result is true.

Here we need to take first case since we need end result as false.

So ~q should be false. There by q value is true

q value is true

wo values of p and q are true, true

Hello,

since we know that:

p->(~p^~q) is false

the truth table is as follows:

p              q                  p ^q                       ~(p^q)              p->n(p^q)

T               T                     T                             F                      F

T                F                     F                            T                      T

F                 T                     F                             T                     T

F                 F                     F                             T                      T

SO  both p and q are True that is the the truth value of p and q are T.

I hope this helps.

All the best!