Let, a be the first term of series and r be the common ratio.
So, by question we can write-

Sum of 3rd and 4th terms-
ar^2+ar^3 = 60
Or, ar^2 (1+r) = 60 .......(1)

Sum of 6th and 7th terms-
ar^5+ar^6 = 480
Or, ar^5 (1+r) = 480 ........(2)

Now, ar^2(1+r)/60 = ar^5(1+r)/480
Or, r= ....... (solve the equation, you will get r).
Now put the value of r in eq. 1 or 2. You will get the value of a.
Now, 10th term will be-
a * r^(10-1) = ...... (solve it by putting the value of a and r)