Question : If the 9-digit number $72 x 8431y 4$ is divisible by 36, what is the value of $(\frac{x}{y}-\frac{y}{x})$ for the smallest possible value of $y$, given that $x$ and $y$ are natural numbers?
Option 1: $1 \frac{5}{7}$
Option 2: $2 \frac{1}{10}$
Option 3: $1 \frac{2}{5}$
Option 4: $2 \frac{9}{10}$
Correct Answer: $2 \frac{1}{10}$
Solution : If $72 x 8431y 4$ is divisible by 36, Then, $72 x 8431y 4$ is divisible by 4 and 9. Since it is divisible by 4, $y4$ is divisible by 4. On putting $y=2, y4 = 24$ which is divisible by 4. $\therefore$ The smallest possible value of $y$ is 2. Now $72 x 8431y 4$ becomes $72 x 84312 4$ As it is divisible by 9, $7+2+x+8+4+3+1+2+4=31+x$ is divisible by 9 ⇒ $x=5$ $\therefore x=5, y=2$ $(\frac{x}{y}-\frac{y}{x})=(\frac{5}{2}-\frac{2}{5})=\frac{25-4}{10}=\frac{21}{10}=2\frac{1}{10}$ Hence, the correct answer is $2\frac{1}{10}$.
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Question : If the 9-digit number 97x4562y8 is divisible by 88, what is the value of $\left(x^2+y^2\right)$ for the smallest value of y, given that x and y are natural numbers?
Option 1: 64
Option 2: 68
Option 3: 76
Option 4: 80
Question : If a nine-digit number 785$x$3678$y$ is divisible by 72, then the value of ($x$ + $y$) is:
Option 1: 20
Option 2: 12
Option 3: 10
Option 4: 5
Question : If $\frac{x}{4 y}=\frac{3}{4}$ then, the value of $\frac{2 x+3 y}{x–2 y}$ is:
Option 1: 7
Option 2: 9
Option 3: 6
Option 4: 8
Question : If $\frac{x^{3}+3y^{2}x}{y^{3}+3x^{2}y}=\frac{35}{19}$, what is $\frac{x}{y} =?$
Option 1: $\frac{7}{6}$
Option 2: $\frac{5}{6}$
Option 3: $\frac{5}{1}$
Option 4: $\frac{7}{1}$
Question : If the six-digit number 479xyz is exactly divisible by 7, 11, and 13, then {(y + z) ÷ x} is equal to:
Option 1: $4$
Option 2: $\frac{11}{9}$
Option 3: $\frac{7}{13}$
Option 4: $\frac{13}{7}$
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