Question : If the area of the non-spherical portion of a solid hemisphere is 1,560 m2, then the total surface area of the hemisphere is:
Option 1: 6,240 m2
Option 2: 4,680 m2
Option 3: 5,140 m2
Option 4: 3,120 m2
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Correct Answer: 4,680 m2
Solution : Given: The area of the non-spherical portion of a solid hemisphere is 1560 m2. So, $\pi r^2=1560$ --------------(1) The total surface area of the hemisphere = $3\pi r^2$ where $r$ is the radius. Substitute the value of $\pi r^2$ from the equation (1), ⇒ $3\pi r^2=3\times 1560=4,680$ m2 Hence, the correct answer is 4,680 m2.
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Question : The curved surface area is thrice as big as the base area of a cone. If the diameter of the cone is 1 cm. Then what is the total surface area (in cm2) of the cone?
Option 1: $\pi$
Option 2: $3\pi $
Option 3: $2\pi$
Option 4: $4\pi $
Question : Find the surface area of a spherical ball that has a radius of 1.1 cm.
Option 1: 16 cm2
Option 2: 12.1 cm2
Option 3: 11.2 cm2
Option 4: 15.2 cm2
Question : The side of a square is equal to 40% of the radius of a sphere. If the volume of the sphere is $\frac{500 \pi}{3} \mathrm{~m}^3$, then what is the area of the square?
Option 1: 2 m2
Option 2: 1 m2
Option 3: 9 m2
Option 4: 4 m2
Question : Find $\frac{1}{21}$th of the volume of a hemisphere whose radius is 4.2 m.
Option 1: 6.6 m3
Option 2: 7.3 m3
Option 3: 8.2 m3
Option 4: 7.1 m3
Question : The curved surface area of a cylinder, whose height is 10 cm, is 1320 cm2. What is the volume of this cylinder? [Use $\pi$ $\left.=\frac{22}{7}\right]$
Option 1: 1388 m3
Option 2: 0.001368 m3
Option 3: 0.1386 m3
Option 4: 0.01386 m3
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