Its 66. Take first even number as a , second as a+2 , third as a+4, fourth as a+6 , fifth as a+8 , sixth as a+10 . (As all are consecutive numbers) so taking sum of all numbers and divide it by 6 and equal to 25 . Value a was found to be 20. Now finding sum of first three numbers by putting value of a to it.
Hope it helps . Thank you
Hello Aspirant
The average of 6 consecutive even numbers can never be 25. So, please correct your question.
I hope you will resend your question.
Thanks
Question : The sum of three consecutive even numbers is 28 more than the average of these three numbers. Then the smallest of these three numbers is:
Option 1: 6
Option 2: 12
Option 3: 14
Option 4: 16
Question : The average of 6 consecutive even numbers is 35. What will be the sum of the smallest and largest even number among these 6 numbers?
Option 1: 68
Option 2: 72
Option 3: 70
Option 4: 66
Question : If the square of the sum of three positive consecutive natural numbers exceeds the sum of their squares by 292, what is the largest of the three numbers?
Option 1: 5
Option 2: 6
Option 3: 3
Option 4: 8
Question : If the average of 6 consecutive even numbers is 25, the difference between the largest and the smallest number is:
Option 1: 8
Option 2: 10
Option 3: 12
Option 4: 14
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