298 Views

if the circle x^2+y^2+ax+by-12=0has the center at 2,3 then find a,b and the radius of the circle


lasyapriya821 9th Oct, 2020
Answer (1)
Tunir Sikdar 9th Oct, 2020

Hi,

The general equation of a circle is ax^2+2hxy+by^2+2gx+2fy+c=0.

Here a=1 b=1 h=0

So equation is x^2 + y^2 + 2gx + 2fy + c = 0

In such equations,

centre = (-g,-f)

radius = √(g^2 + f^2 - c )

Equation of the circle here is x^2 + y^2 + ax + by – 12 = 0

Centre = (-a/2, -b/2) = (2, 3)
−a/2 = 2, − b/2 = 3
a = – 4, b = – 6


g = –2, f = –3, c = –12
radius = √(g^2 + f^2 - c) = √(4 + 9 + 12) = 5

Related Questions

UPES B.Tech Admissions 2026
Apply
Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
UPES Integrated LLB Admission...
Apply
Ranked #18 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS Rankings | 16 LPA Highest CTC
Presidency University MBA Adm...
Apply
NAAC A+ Accredited | Highest CTC 10 LPA | Top Recruiters : Amazon, Accenture, KPMG, EY, Capgemini & many more
Nirma University Law Admissio...
Apply
Grade 'A+' accredited by NAAC | Ranked 33rd by NIRF 2025
UPES M.Tech Admissions 2026
Apply
Ranked #45 Among Universities in India by NIRF | 1950+ Students Placed 91% Placement, 800+ Recruiters
UPES | BBA Admissions 2026
Apply
#36 in NIRF, NAAC ‘A’ Grade | 100% Placement, up to 30% meritorious scholarships
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books