Question : If the side of an equilateral triangle is 16 cm, then what is its area?
Option 1: $81 \sqrt{3} \mathrm{~cm}^2$
Option 2: $48 \sqrt{3} \mathrm{~cm}^2$
Option 3: $32 \sqrt{3} \mathrm{~cm}^2$
Option 4: $64 \sqrt{3} \mathrm{~cm}^2$
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Correct Answer: $64 \sqrt{3} \mathrm{~cm}^2$
Solution : Given: Sides of the triangle = 16 cm Area of an equilateral triangle with sides $a$ = $\frac{\sqrt3}{4} (a)^2$ $=\frac{\sqrt3}{4}\times 16\times 16$ $= 64\sqrt{3}$ Hence, the correct answer is $64\sqrt3\ \mathrm{cm^2}$.
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Question : The height of an equilateral triangle is $9 \sqrt{3} \mathrm{~cm}$. What is the area of this equilateral triangle?
Option 1: $92 \sqrt{3} \mathrm{~cm}^2$
Option 2: $67 \sqrt{3} \mathrm{~cm}^2$
Option 3: $49 \sqrt{3} \mathrm{~cm}^2$
Option 4: $81 \sqrt{3} \mathrm{~cm}^2$
Question : Find the area of an equilateral triangle whose sides are 16 cm.
Option 1: $60\sqrt{3}\mathrm{~cm}^2$
Option 2: $62\sqrt{3} \mathrm{~cm}^2$
Option 3: $64\sqrt{3} \mathrm{~cm}^2$
Option 4: $66\sqrt{3} \mathrm{~cm}^2$
Question : The perimeter of an equilateral triangle is 48 cm. Find its area (in cm2).
Option 1: $81\sqrt{3}$
Option 2: $8\sqrt{3}$
Option 3: $25\sqrt{3}$
Option 4: $64\sqrt{3}$
Question : The side of an equilateral triangle is 36 cm. What is the radius of the circle circumscribing this equilateral triangle?
Option 1: $13 \sqrt{3} \mathrm{~cm}$
Option 2: $10 \sqrt{3} \mathrm{~cm}$
Option 3: $12 \sqrt{3} \mathrm{~cm}$
Option 4: $9 \sqrt{3} \mathrm{~cm}$
Question : The centroid of an equilateral triangle PQR is L. If PQ = 6 cm, the length of PL is :
Option 1: $4 \sqrt{3} \mathrm{~cm}$
Option 2: $3\sqrt{3} \mathrm{~cm}$
Option 3: $2\sqrt{3} \mathrm{~cm}$
Option 4: $5\sqrt{3} \mathrm{~cm}$
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