Question : If $\tan(5x-10^{\circ})=\cot(5y+20^{\circ})$, the value of $(x+y)$ is:
Option 1: $15^{\circ}$
Option 2: $16^{\circ}$
Option 3: $24^{\circ}$
Option 4: $20^{\circ}$
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Correct Answer: $16^{\circ}$
Solution : Given: $\tan(5x-10^{\circ})=\cot(5y+20^{\circ})$ ⇒ $\tan(5x-10^{\circ})=\tan(90^{\circ}-(5y+20^{\circ}))$ ⇒ $5x-10^{\circ}=90^{\circ}-5y-20^{\circ}$ ⇒ $5x+5y=80^{\circ}$ ⇒ $x+y=16^{\circ}$ Hence, the correct answer is $16^{\circ}$.
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Question : What is the value of $\frac{\tan 45^{\circ}-\tan 15^{\circ}}{1+\tan 45^{\circ} \tan 15^{\circ}}$?
Option 1: $\sqrt{3}$
Option 2: $\frac{1}{\sqrt{2}}$
Option 3: $\frac{1}{\sqrt{3}}$
Option 4: ${\sqrt{2}}$
Question : Using trigonometric formulas, find the value of $(\frac{\sin (x-y)}{\sin (x+y)})(\frac{\tan x+\tan y}{\tan x-\tan y})$
Option 1: –2
Option 2: 2
Option 3: 0
Option 4: 1
Question : If $\frac{3–5x}{2x}+\frac{3–5y}{2y}+\frac{3–5z}{2z}=0$, the value of $\frac{2}{x}+\frac{2}{y}+\frac{2}{z}$ is:
Option 1: 20
Option 2: 5
Option 3: 10
Option 4: 15
Question : The value of $\tan 5^{\circ} \tan 25^{\circ} \tan 45^{\circ} \tan 65^{\circ} \tan 85^{\circ}$ is ______.
Option 1: 4
Option 2: 3
Option 3: 1
Option 4: 2
Question : If $x\sin ^{2}60^{\circ}-\frac{3}{2}\sec 60^{\circ}\tan^{2}30^{\circ}+\frac{4}{5}\sin ^{2}45^{\circ}\tan ^{2}60^{\circ}=0$, then $x$ is:
Option 1: $-\frac{1}{15}$
Option 2: $–4$
Option 3: $-\frac{4}{15}$
Option 4: $–2$
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