Question : If $\tan A=\frac{2}{5}$, then find the value of $\frac{\sec ^2 A}{\operatorname{cosec}^2 A}$.
Option 1: $\frac{2}{5}$
Option 2: $\frac{4}{25}$
Option 3: $\frac{9}{25}$
Option 4: $\frac{3}{5}$
Correct Answer: $\frac{4}{25}$
Solution : Given: $\tan A=\frac{2}{5}$ ⇒ $\cot A=\frac{5}{2}$ Now, $\sec^2 A = 1+ \tan^2 A$ ⇒ $\sec^2 A = 1+ (\frac{2}{5})^2$ ⇒ $\sec^2 A = 1+ (\frac{4}{25})$ ⇒ $\sec^2 A = (\frac{29}{25})$ Also, $\operatorname{cosec}^2 A = 1+ \cot^2 A$ ⇒ $\operatorname{cosec}^2 A = 1+ (\frac{5}{2})^2$ ⇒ $\operatorname{cosec}^2 A = 1+ (\frac{25}{4})$ ⇒ $\operatorname{cosec}^2 A = (\frac{29}{4})$ So, $\frac{\sec ^2 A}{\operatorname{cosec}^2 A} = \frac{\frac{29}{25}}{\frac{29}{4}}$ ⇒ $\frac{\sec ^2 A}{\operatorname{cosec}^2 A} = \frac{4}{25}$ Hence, the correct answer is $\frac{4}{25}$.
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Question : If $\frac{1}{\operatorname{cosec} \theta+1}+\frac{1}{\operatorname{cosec} \theta-1}=2 \sec \theta, 0^{\circ}<\theta<90^{\circ}$, then the value of $\frac{\tan \theta+2 \sec \theta}{\operatorname{cosec} \theta}$ is:
Option 1: $\frac{4+\sqrt{2}}{2}$
Option 2: $\frac{2+\sqrt{3}}{2}$
Option 3: $\frac{4+\sqrt{3}}{2}$
Option 4: $\frac{2+\sqrt{2}}{2}$
Question : The value of $\sqrt{\frac{1+\sin A}{1-\sin A}}$ is:
Option 1: $\sec A-\tan A$
Option 2: $\operatorname{cosec} A+\cot A$
Option 3: $\sec A+\tan A$
Option 4: $\operatorname{cosec} A-\cot A$
Question : If $\operatorname{cosec} A+\cot A=3$, $0 \leq A \leq 90^{\circ}$, then find the value of cos A.
Option 1: $\frac{3}{4}$
Option 2: $\frac{2}{5}$
Option 3: $\frac{3}{5}$
Option 4: $\frac{4}{5}$
Question : If $\tan (11 \theta)=\cot (7 \theta)$, then what is the value of $\sin ^2(6 \theta)+\sec ^2(9 \theta)+\operatorname{cosec}^2(12 \theta) ?$
Option 1: $\frac{23}{6}$
Option 2: $\frac{35}{12}$
Option 3: $\frac{31}{12}$
Option 4: $\frac{43}{12}$
Question : If $\sec\theta+\tan\theta=2$, then the value of $\sec\theta$ is:
Option 1: $\frac{4}{5}$
Option 2: $5$
Option 3: $\frac{5}{4}$
Option 4: $\sqrt{2}$
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