Question : If $\frac{21\cos A+3\sin A}{3\cos A+4\sin A}=2$, then find the value of cot A.
Option 1: $\frac{9}{11}$
Option 2: $\frac{11}{9}$
Option 3: $\frac{1}{3}$
Option 4: $\frac{11}{10}$
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Correct Answer: $\frac{1}{3}$
Solution : Given: $\frac{21 \cos A+3 \sin A}{3 \cos A+4 \sin A}=2$ Dividing numerator and denominator by $\sin A$ gives us, $\frac{21 \cot A+3 }{3 \cot A+4} =2$ ⇒ $21 \cot A+3 =6 \cot A+8 $ ⇒ $15\cot A=5$ ⇒ $\cot A = \frac{1}{3}$ Hence, the correct answer is $\frac{1}{3}$.
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Question : What is the value of the given expression if $3\cot A=\frac{7}{3}$? $\frac{3 \cos A+2 \sin A}{3 \cos A-2 \sin A}$
Option 1: $\frac{2}{3}$
Option 2: $\frac{1}{3}$
Option 3: $13$
Option 4: $1$
Question : If $\frac{\sin x-\cos x}{\sin x+\cos x}=\frac{2}{5}$, then the value of $\frac{1+\cot ^2 x}{1-\cot ^2 x}$ is:
Option 1: 2.25
Option 2: 1.45
Option 3: 3.75
Option 4: 5.25
Question : If $\sin t+\cos t=\frac{4}{5}$, then find $\sin t.\cos t$.
Option 1: $\frac{9}{50}$
Option 2: $-\frac{9}{50}$
Option 3: $\frac{9}{25}$
Option 4: $-\frac{9}{25}$
Question : If $4 \tan \theta=3$, then $\frac{4 \sin \theta-\cos \theta+1}{4 \sin \theta+\cos \theta-1}=?$
Option 1: $\frac{14}{11}$
Option 2: $\frac{12}{11}$
Option 3: $\frac{10}{11}$
Option 4: $\frac{13}{11}$
Question : If $\frac{\sin \theta+\cos \theta}{\sin \theta-\cos \theta}=\frac{3}{2}$, then the value of $\sin ^4 \theta-\cos ^4 \theta$ is:
Option 1: $\frac{5}{12}$
Option 2: $\frac{12}{13}$
Option 3: $\frac{11}{12}$
Option 4: $\frac{5}{13}$
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