Question : If $(x+\frac{1}{x})=3$, then $(x^8+\frac{1}{x^8})$ is equal to:
Option 1: 2201
Option 2: 2203
Option 3: 2207
Option 4: 2213
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Correct Answer: 2207
Solution : Given: $(x+\frac{1}{x})=3$ Squaring both sides of the above equation, we get, ⇒ $(x^2+\frac{1}{x^2}+2)=9$ ⇒ $x^2+\frac{1}{x^2}=7$ Again, squaring both sides of the above equation, we get, ⇒ $(x^2+\frac{1}{x^2})^2=7^2$ ⇒ $x^4+\frac{1}{x^4}+2=49$ ⇒ $x^4+\frac{1}{x^4}=47$ Again, squaring both sides of the above equation, we get, ⇒ $(x^4+\frac{1}{x^4})^2=47^2$ ⇒ $x^8+\frac{1}{x^8}+2=2209$ ⇒ $x^8+\frac{1}{x^8}=2207$ Hence, the correct answer is 2207.
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Question : If $2\cot x=5$, then what is $\frac{2 \cos x-\sin x}{2 \cos x+\sin x}$ equal to?
Option 1: $\frac{3}{4}$
Option 2: $\frac{1}{3}$
Option 3: $\frac{5}{6}$
Option 4: $\frac{2}{3}$
Question : If $x+3y=-3x+y$, then $\frac{x^{2}}{2y^{2}}$ is equal to:
Option 1: $\frac{1}{8}$
Option 2: $\frac{1}{2}$
Option 3: $\frac{1}{4}$
Option 4: $4$
Question : When $2x+\frac{2}{x}=3$, then the value of ($x^3+\frac{1}{x^3}+2)$ is:
Option 1: $\frac{2}{7}$
Option 2: $\frac{7}{8}$
Option 3: $\frac{7}{2}$
Option 4: $\frac{8}{7}$
Question : If $2x+\frac{2}{x}=3$, then the value of $x^{3}+\frac{1}{x^{3}}+2$ is:
Option 2: $\frac{4}{5}$
Option 3: $\frac{5}{8}$
Option 4: $\frac{7}{8}$
Question : If $2x-\frac{2}{x}=1(x \neq 0)$, then the the value of $(x^3-\frac{1}{x^3})$ is:
Option 1: $\frac{13}{4}$
Option 2: $\frac{13}{8}$
Option 3: $\frac {17}{4}$
Option 4: $\frac{17}{8}$
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