Question : If $5x+\frac{1}{x}=10$, then $x^2+\frac{1}{25x^2}$ is equal to:
Option 1: $2\frac{1}{5}$
Option 2: $3\frac{1}{5}$
Option 3: $3\frac{3}{5}$
Option 4: $2\frac{3}{5}$
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Correct Answer: $3\frac{3}{5}$
Solution : Given: $5x+\frac{1}{x}=10$ We know that the algebraic identity, $(a+b)^2=a^2+b^2+2ab$. $5x+\frac{1}{x}=10$ On squaring both sides of the above equation, we get, $(5x+\frac{1}{x})^2=10^2$ ⇒ $25x^2+\frac{1}{x^2}+10=100$ ⇒ $25x^2+\frac{1}{x^2}=90$ Divide by 25 on both sides of the above equation, we get, $x^2+\frac{1}{25x^2}=\frac{90}{25}$ ⇒ $x^2+\frac{1}{25x^2}=\frac{18}{5}=3\frac{3}{5}$ Hence, the correct answer is $3\frac{3}{5}$.
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Question : If $(x+\frac{1}{x})$ = 5, then the value of $\frac{5x}{x^{2}+5x+1}$ is:
Option 1: $\frac{1}{3}$
Option 2: $\frac{1}{4}$
Option 3: $\frac{1}{2}$
Option 4: $\frac{1}{5}$
Question : If $x=2+\sqrt3$, then the value of $\frac{x^{2}-x+1}{x^{2}+x+1}$ is:
Option 1: $\frac{2}{3}$
Option 2: $\frac{3}{4}$
Option 3: $\frac{4}{5}$
Option 4: $\frac{3}{5}$
Question : If $2\cot x=5$, then what is $\frac{2 \cos x-\sin x}{2 \cos x+\sin x}$ equal to?
Option 1: $\frac{3}{4}$
Option 2: $\frac{1}{3}$
Option 3: $\frac{5}{6}$
Option 4: $\frac{2}{3}$
Question : If $x=\frac{\sqrt{5}+1}{\sqrt{5}-1}$ and $y=\frac{\sqrt{5}-1}{\sqrt{5}+1}$, then the value of $\frac{x^{2}+xy+y^{2}}{x^{2}-xy+y^{2}}$ is:
Option 2: $\frac{4}{3}$
Option 3: $\frac{3}{5}$
Option 4: $\frac{5}{3}$
Question : If $x^4+y^4+x^2 y^2=17 \frac{1}{16}$ and $x^2-x y+y^2=5 \frac{1}{4}$, then one of the values of $(x-y)$ is:
Option 1: $\frac{5}{2}$
Option 3: $\frac{5}{4}$
Option 4: $\frac{3}{2}$
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