Question : If $x+3y=-3x+y$, then $\frac{x^{2}}{2y^{2}}$ is equal to:
Option 1: $\frac{1}{8}$
Option 2: $\frac{1}{2}$
Option 3: $\frac{1}{4}$
Option 4: $4$
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Correct Answer: $\frac{1}{8}$
Solution : Given: $x+3y=-3x+y$ Solution: ⇒ $x+3y+3x-y=0$ ⇒ $4x+2y=0$ ⇒ $2(2x+y)=0$ ⇒ $2x+y=0$ ⇒ $y=–2x$ Put the value of $y$ in $\frac{x^{2}}{2y^{2}}$ = $\frac{x^{2}}{2(–2x)^{2}}$ = $\frac{x^{2}}{8x^{2}}$ = $\frac{1}{8}$ Hence, the correct answer is $\frac{1}{8}$.
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Question : If $x+y+z=0$, then what is the value of $\frac{x^2}{3z}+\frac{y^3}{3xz}+\frac{z^2}{3x}$?
Option 1: $0$
Option 2: $xz$
Option 3: $y$
Option 4: $3y$
Question : If $(x+y):(x-y)=11:1$, find the value of $(\frac{5x+3y}{x-2y})$.
Option 1: $\frac{45}{4}$
Option 2: $\frac{4}{45}$
Option 3: $-\frac{45}{4}$
Option 4: $-\frac{4}{45}$
Question : The graphs of the equations $4 x+\frac{1}{3} y=\frac{8}{3}$ and $\frac{1}{2} x+\frac{3}{4} y+\frac{5}{2}=0$ intersect at a point P. The point P also lies on the graph of the equation:
Option 1: $x + 2y - 5 = 0$
Option 2: $3x - y - 7 = 0$
Option 3: $x - 3y - 12= 0$
Option 4: $4x - y + 7= 0$
Question : If $xy(x+y)=m$, then the value of $(x^3+y^3+3m)$ is:
Option 1: $\frac{m^3}{xy}$
Option 2: $\frac{m^3}{(x+y)^3}$
Option 3: $\frac{m^3}{x^3y^3}$
Option 4: $mx^3y^3$
Question : If $x+y+z=0$, then what is the value of $\frac{\left (3y^{2}+x^{2}+z^{2} \right )}{\left (2y^{2}-xz \right)}$?
Option 1: $2$
Option 2: $1$
Option 3: $\frac{3}{2}$
Option 4: $\frac{5}{3}$
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