Question : If $\sin \theta +\sin ^{2}\theta =1$, then the value of $\cos ^{2}\theta +\cos ^{4}\theta$ is:
Option 1: 2
Option 2: 4
Option 3: 0
Option 4: 1
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Correct Answer: 1
Solution : Given: $\sin \theta +\sin ^{2}\theta =1$ We know that, $\sin ^{2}\theta+\cos ^{2}\theta=1$ ⇒ $\sin \theta=1-\sin ^{2}\theta=\cos ^{2}\theta$ To find: $\cos ^{2}\theta +\cos ^{4}\theta$ $=\cos ^{2}\theta(1 +\cos ^{2}\theta)$ Putting the values, we get: $=\sin\theta(1 +\sin\theta)$ $\sin \theta +\sin ^{2}\theta = 1$ Hence, the correct answer is 1.
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Question : If $\sin \theta-\cos \theta=0$, then find the value of $\left(\sin^3 \theta-\cos^3 \theta\right)$.
Option 1: $0$
Option 2: $2$
Option 3: $1$
Option 4: $\frac{1}{\sqrt{2}}$
Question : If $\frac{(3 \sin \theta-\cos \theta)}{(\cos \theta+\sin \theta)}=1$, then the value of $\cot \theta$ is:
Option 1: 3
Option 2: 0
Option 3: 1
Option 4: 2
Question : If $2 \sin \theta+2 \sin ^2 \theta=2$, then the value of $2 \cos ^4 \theta+2 \cos ^2 \theta$ is:
Option 1: 4
Option 2: 2
Option 4: 0
Question : If $\sin \theta+\sin ^2 \theta=1$, then the value of $\cos ^2 \theta+\cos ^4 \theta$ is equal to:
Option 1: 5
Option 2: $\frac{1}{2}$
Option 4: $0$
Question : If $x\sin^{3}\theta +y\cos^{3}\theta=\sin\theta\cos\theta$ and $x\sin\theta-y\cos\theta=0$, then the value of $\left ( x^{2}+y^{2} \right )$ equals:
Option 1: $1$
Option 3: $\frac{3}2$
Option 4: $2$
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