Question : If $x=\frac{3}{2}$, then the value of $27x^{3}-54x^{2}+36x-11$ is:
Option 1: $11\frac{3}{8}$
Option 2: $11\frac{5}{8}$
Option 3: $12\frac{3}{8}$
Option 4: $12\frac{5}{8}$
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Correct Answer: $12\frac{5}{8}$
Solution : Given: $27x^{3}–54x^{2}+36x–11$ Putting the value of $x=\frac{3}{2}$ in the above equation $27×(\frac{3}{2})^{3}–54×(\frac{3}{2})^{2}+36×\frac{3}{2}–11$ = $27×(\frac{27}{8})–54×(\frac{9}{4})+36×\frac{3}{2}–11$ = $\frac{729}{8}–\frac{486}{4}+\frac{108}{2}–11$ = $\frac{729–972+432–88}{8}$ = $\frac{101}{8}$ = $12\frac{5}{8}$ Hence, the correct answer is $12\frac{5}{8}$.
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Question : If $x-\frac{1}{x}=5, x \neq 0$, then what is the value of $\frac{x^6+3 x^3-1}{x^6-8 x^3-1} ?$
Option 1: $\frac{3}{8}$
Option 2: $\frac{13}{12}$
Option 3: $\frac{4}{9}$
Option 4: $\frac{11}{13}$
Question : If $2x+\frac{2}{x}=3$, then the value of $x^{3}+\frac{1}{x^{3}}+2$ is:
Option 1: $\frac{3}{4}$
Option 2: $\frac{4}{5}$
Option 3: $\frac{5}{8}$
Option 4: $\frac{7}{8}$
Question : If $x=2+\sqrt3$, then the value of $\frac{x^{2}-x+1}{x^{2}+x+1}$ is:
Option 1: $\frac{2}{3}$
Option 2: $\frac{3}{4}$
Option 3: $\frac{4}{5}$
Option 4: $\frac{3}{5}$
Question : If $x^{2} -3x +1=0$, then the value of $\frac{\left(x^4+\frac{1}{x^2}\right)}{\left(x^2+5 x+1\right)}$ is:
Option 1: $\frac{9}{4}$
Option 2: $\frac{27}{8}$
Option 3: $\frac{5}{2}$
Option 4: $2$
Question : If $(x+\frac{1}{x})$ = 5, then the value of $\frac{5x}{x^{2}+5x+1}$ is:
Option 1: $\frac{1}{3}$
Option 2: $\frac{1}{4}$
Option 3: $\frac{1}{2}$
Option 4: $\frac{1}{5}$
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