Question : If $(4a-3)^2=0$, then the value of $64a^3-48a^2+12a+13$ is:
Option 1: 0
Option 2: 11
Option 3: 22
Option 4: 33
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Correct Answer: 22
Solution : Given: $(4a-3)^2=0$ $⇒4a-3=0$ $⇒a=\frac{3}{4}$ Substitute the value of $a$ in the equation below, we get, $64a^3-48a^2+12a+13$ $=(4a)^3-3×(4a)^2×1+3×4a×(1)^2-(1)^3+14$ $=(4a-1)^3+14$ $=(4×\frac{3}{4}-1)^3+14$ $=8+14$ $=22$ Hence, the correct answer is 22.
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Question : If $(x-\frac{1}{3})^2+(y-4)^2=0$, then what is the value of $\frac{y+x}{y-x}$?
Option 1: $\frac{11}{13}$
Option 2: $\frac{13}{11}$
Option 3: $\frac{16}{9}$
Option 4: $\frac{9}{16}$
Question : If $a=26$ and $b=22$, then the value of $\frac{a^3-b^3}{a^2-b^2}-\frac{3 a b}{a+b}$ is_______.
Option 1: $\frac{5}{3}$
Option 3: $\frac{1}{3}$
Option 4: $\frac{11}{13}$
Question : If $(x^2-2x+1)=0$, then the value of $x^4+\frac{1}{x^4}$ is:
Option 2: 1
Option 3: 2
Option 4: 3
Question : If $y+\frac{1}{y}=11$, then the value of $y^3-\frac{1}{y^3}$ is:
Option 1: $345 \sqrt{13}$
Option 2: $360 \sqrt{13}$
Option 3: $352 \sqrt{13}$
Option 4: $368 \sqrt{13}$
Question : If $x = \sqrt[3]{5} + 2$, then the value of $x^3-6x^2+12x-13$ is:
Option 1: $–1$
Option 2: $1$
Option 3: $2$
Option 4: $0$
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