Question : If $x+\frac{1}{x}=2$, then the value of $x^{11}+\frac{1}{x^{20}}$ is:
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: 7
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Correct Answer: 2
Solution : Given, $x+\frac{1}{x}=2$ ⇒ $x^2+1=2x$ ⇒ $x^2+1-2x=0$ ⇒ $(x-1)^2=0$ ⇒ $x-1=0$ $\therefore x=1$ Consider, $x^{11}+\frac{1}{x^{20}}$ = $1^{11}+\frac{1}{1^{20}}$ = $1+1$ = $2$ Hence, the correct answer is 2.
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Question : If $x+\frac{1}{x}=-2$, then what is the value of $x^7+x^{-7}+x^2+x^{-2} ?(\mathrm{x}<0)$
Option 1: 4
Option 2: 2
Option 3: 1
Option 4: 0
Question : If $x+\frac{2}{x}=1$, then the value of $\frac{x^2+7x+2}{x^2+13x+2}$ is:
Option 1: $\frac{5}{7}$
Option 2: $\frac{3}{7}$
Option 3: $\frac{4}{7}$
Option 4: $\frac{2}{7}$
Question : If $\frac{x}{y}=\frac{4}{5}$, then the value of $(\frac{4}{7}+\frac{2y–x}{2y+x})$ is:
Option 1: $\frac{3}{7}$
Option 2: $1\frac{1}{7}$
Option 3: $1$
Option 4: $2$
Question : If $2 x+\frac{2}{x}=5$, then the value of $\left(x^3+\frac{1}{x^3}+2\right)$ will be:
Option 1: $\frac{81}{11}$
Option 2: $\frac{81}{7}$
Option 3: $\frac{71}{8}$
Option 4: $\frac{81}{8}$
Question : If $2(x^{2}+\frac{1}{x^{2}})-(x-\frac{1}{x})-7=0$, then two values of $x$ are:
Option 1: $1, 2$
Option 2: $2,-\frac{1}{2}$
Option 3: $0, 1$
Option 4: $\frac{1}{2},1$
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