Question : If $x=\sqrt{3}-\frac{1}{\sqrt{3}}, y=\sqrt{3}+\frac{1}{\sqrt{3}}$, then the value of $\frac{x^2}{y}+\frac{y^2}{x}$ is:
Option 1: $\sqrt{3}$
Option 2: $3\sqrt{3}$
Option 3: $16\sqrt{3}$
Option 4: $2\sqrt{3}$
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Correct Answer: $3\sqrt{3}$
Solution : Given: $x=\sqrt{3}-\frac{1}{\sqrt{3}}, y=\sqrt{3}+\frac{1}{\sqrt{3}}$ $⇒x=\frac{2}{\sqrt{3}}, y =\frac{4}{\sqrt{3}}$ Now, $\frac{x^2}{y}+\frac{y^2}{x}$ $=\frac{(\frac{2}{\sqrt{3}})^2}{\frac{4}{\sqrt{3}}}+\frac{(\frac{4}{\sqrt{3}})^2}{\frac{2}{\sqrt{3}}}$ $=\frac{1}{\sqrt{3}}+\frac{8}{\sqrt{3}}$ $=3\sqrt{3}$ Hence, the correct answer is $3\sqrt{3}$.
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Question : If $x^{4}+\frac{1}{x^{4}}=16$, then what is the value of $x^{2}+\frac{1}{x^{2}}$?
Option 1: $3 \sqrt{2}$
Option 2: $2 \sqrt{2}$
Option 3: $5 \sqrt{2 }$
Option 4: $4 \sqrt{2}$
Question : If $x^2+y^2=427$ and $xy=202$, then find the value of $\frac{x+y}{x-y}$.
Option 1: $\sqrt{\frac{835}{23}}$
Option 2: $\sqrt{\frac{830}{29}}$
Option 3: $\sqrt{\frac{831}{23}}$
Option 4: $\sqrt{\frac{830}{23}}$
Question : If $\sin (x - y) = \frac{1}2$ and $\cos (x + y) = \frac{1}2$, then what is the value of $\sin x \cos x + 2\sin^2x + cos^3x \sec x$?
Option 1: $2$
Option 2: $\sqrt{2}+1$
Option 3: $1$
Option 4: $\frac{3}{4}$
Question : If $x+y=4, x^{2}+y^{2}=14$ and $x>y$, then the correct value of $x$ and $y$ is:
Option 1: $2+\sqrt{3} \text{ and } 2-\sqrt{3}$
Option 2: $2-\sqrt{2} \text{ and } \sqrt{3}$
Option 3: $3 \text{ and } 1$
Option 4: $2+\sqrt{3} \text{ and } 2\sqrt{2}$
Question : If $\sqrt{y}=4x$, then $\frac{x^{2}}{y}$ is:
Option 2: $\frac{1}{16}$
Option 3: $\frac{1}{4}$
Option 4: $4$
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