Question : If $a+\frac{1}{a-2}=4$, then the value of $(a-2)^{2}+(\frac{1}{a-2})^{2}$ is:
Option 1: 0
Option 2: 2
Option 3: –2
Option 4: 4
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Correct Answer: 2
Solution : Given: $a+\frac{1}{a-2}=4$ Subtracting 2 from both sides, ⇒ $a-2+\frac{1}{a-2}=2$ Squaring both sides, ⇒ $( a-2)^2+\frac{1}{( a-2)^2} + 2=2^2$ ⇒ $( a-2)^2+\frac{1}{( a-2)^2}=2^2-2$ ⇒ $( a-2)^2+\frac{1}{( a-2)^2}=2$ Hence, the correct answer is 2.
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Question : If $(a+\frac{1}{a})=–2$, then the value of $a^{1000}+a^{–1000}$ is:
Option 1: $2$
Option 2: $0$
Option 3: $1$
Option 4: $\frac{1}{2}$
Question : If $a+\frac{1}{a}=1$, then the value of $\frac{a^2-a+1}{a^2+a+1}$ is $(a\neq 0)$:
Option 1: 1
Option 2: –1
Option 3: 0
Option 4: 2
Question : If $(x+\frac{1}{x})^{2}=3$, then the value of $(x^{3}+\frac{1}{x^{3}})$ is:
Option 2: 1
Option 3: 2
Option 4: –1
Question : If $\frac{3–5x}{2x}+\frac{3–5y}{2y}+\frac{3–5z}{2z}=0$, the value of $\frac{2}{x}+\frac{2}{y}+\frac{2}{z}$ is:
Option 1: 20
Option 2: 5
Option 3: 10
Option 4: 15
Question : If $\frac{a}{b}+\frac{b}{a}=1$, then the value of $(a^3+b^3)$ is:
Option 2: 0
Option 3: –1
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