Question : If $x+\frac{1}{x}=0$, then the value of $x^{5}+\frac{1}{x^{5}}$ is:
Option 1: 2
Option 2: –1
Option 3: 1
Option 4: 0
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Correct Answer: 0
Solution : Given: $x+\frac{1}{x}=0$............................................ $(i)$ Now, $(x^2+\frac{1}{x^2})(x+\frac{1}{x})$ = 0 ⇒ $x^3+\frac{1}{x^3} + x+\frac{1}{x}$= 0 ⇒ $x^3+\frac{1}{x^3}=0$ Also, $(x^4+\frac{1}{x^4})(x+\frac{1}{x})$ = 0 ⇒ $x^5+\frac{1}{x^5} + x^3+\frac{1}{x^3}$= 0 ⇒ $ x^5+\frac{1}{x^5} + 0 = 0$ ⇒ $x^5+\frac{1}{x^5} = 0$ Hence, the correct answer is 0.
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Question : If $\frac{x}{3}+\frac{3}{x}=1$, then the value of $x^3$ is:
Option 1: 1
Option 2: 27
Option 3: 0
Option 4: –27
Question : If $X$ is 20% less than $Y$, then find the values of$\frac{Y–X}{Y}$ and $\frac{X}{X–Y}$.
Option 1: $\frac{1}{5}$ and $-4$
Option 2: $5$ and $-\frac{1}{4}$
Option 3: $\frac{2}{5}$ and $-\frac{5}{2}$
Option 4: $\frac{3}{5}$ and $-\frac{5}{3}$
Question : If $x+\frac{1}{x}=2$, then find the value of $x^{1823}+\frac{1}{x^{1929}}$.
Option 2: 1
Option 4: –1
Question : If $x^{\frac{1}{4}}+x^{\frac{-1}{4}}=2$, then what is the value of $x^{81}+\frac{1}{x^{81}}$?
Option 1: –2
Option 2: 0
Option 4: 2
Question : If $\frac{x}{y}=\frac{4}{5}$, then the value of $(\frac{4}{7}+\frac{2y–x}{2y+x})$ is:
Option 1: $\frac{3}{7}$
Option 2: $1\frac{1}{7}$
Option 3: $1$
Option 4: $2$
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