Question : If $x+\frac{1}{x}=5$, then the value of $\frac{x}{1+x+x^2}$ is:
Option 1: $\frac{1}{5}$
Option 2: $\frac{1}{6}$
Option 3: $5$
Option 4: $6$
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Correct Answer: $\frac{1}{6}$
Solution : Given: $x+\frac{1}{x}=5$ Now, $\frac{x}{1+x+x^2}$ Divide the above expression by $x$ in numerator and denominator, ⇒ $\frac{1}{\frac{1}{x}+1+x}$ $=\frac{1}{x+\frac{1}{x}+1}$ $=\frac{1}{5+1}=\frac{1}{6}$ Hence, the correct answer is $\frac{1}{6}$.
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Question : If $x=2+\sqrt3$, then the value of $\frac{x^{2}-x+1}{x^{2}+x+1}$ is:
Option 1: $\frac{2}{3}$
Option 2: $\frac{3}{4}$
Option 3: $\frac{4}{5}$
Option 4: $\frac{3}{5}$
Question : If $x+\frac{1}{x}=6$, then find the value of $\frac{3 x}{2 x^2-5 x+2}$.
Option 1: $1$
Option 2: $\frac{3}{7}$
Option 3: $\frac{2}{3}$
Option 4: $0$
Question : If $x-\frac{1}{x}=2$, then what is the value of $x^2+\frac{1}{x^2}$?
Option 1: 4
Option 2: 5
Option 3: 3
Option 4: 6
Question : If $x-\frac{1}{x}=5, x \neq 0$, then what is the value of $\frac{x^6+3 x^3-1}{x^6-8 x^3-1} ?$
Option 1: $\frac{3}{8}$
Option 2: $\frac{13}{12}$
Option 3: $\frac{4}{9}$
Option 4: $\frac{11}{13}$
Question : If $x+5+\frac{1}{x+1}=6$, then the value of $(x+1)^{3}+\frac{1}{(x+1)^{3}}$ is:
Option 1: 2
Option 2: 0
Option 3: –2
Option 4: 4
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