Question : If $\sin 2\theta=\frac{\sqrt{3}}{2}$, then the value of $\sin 3\theta$ is equal to $(0^{\circ}\leq \theta\leq 90^{\circ})$:
Option 1: $\frac{1}{2}$
Option 2: $1$
Option 3: $0$
Option 4: $\frac{\sqrt{3}}{2}$
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Correct Answer: $1$
Solution : $\sin 2\theta=\frac{\sqrt{3}}{2}=\sin 60^{\circ}$ $⇒2\theta = 60^{\circ}$ $⇒\theta = 30^{\circ}$ We know that, $\sin 3\theta = \sin 90^{\circ} = 1$ Hence, the correct answer is $1$.
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Question : If $\sin (\theta +18^{\circ})=\cos 60^{\circ}(0< \theta < 90^{\circ})$, then the value of $\cos 5\theta$ is:
Option 2: $0$
Option 3: $\frac{1}{\sqrt{2}}$
Option 4: $1$
Question : If $4 \sin ^2 \mathrm{A}-3=0$ and $0 \leq \mathrm{A} \leq 90^{\circ}$, then $3 \sin \mathrm{A}-4 \sin ^3 \mathrm{A}$ is:
Option 2: $\sqrt{\frac{3}{2}}$
Question : If $\theta$ is a positive acute angle and $4\cos ^{2}\theta -4\cos \theta +1=0$, then the value of $\tan (\theta -15^{\circ})$is equal to:
Option 1: $0$
Option 3: $\sqrt{3}$
Option 4: $\frac{1}{\sqrt{3}}$
Question : If $(\sin \theta-\cos \theta)=0$, then the value of $\sin\;(\pi-\theta)+\sin \left(\frac{\pi}{2}-\theta\right)$ is:
Option 1: $1$
Option 4: $\sqrt{2}$
Question : If $\frac{\sin \theta}{\cot \theta+\operatorname{cosec} \theta}=1$, then what is the value of $\theta$?
Option 1: $30^{\circ}$
Option 2: $90^{\circ}$
Option 3: $0^{\circ}$
Option 4: $45^{\circ}$
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