Question : If $ \frac{k-k \cot ^2 30^{\circ}}{1+\cot ^2 30^{\circ}}=\sin ^2 60^{\circ}+4 \tan ^2 45^{\circ}-\operatorname{cosec}^2 60^{\circ}$, then the value of k (correct to two decimal places) is:
Option 1: 5.55
Option 2: – 6.83
Option 3: – 5.58
Option 4: 6.83
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Correct Answer: – 6.83
Solution : Computing RHS, $\sin ^2 60^{\circ}+4 \tan ^2 45^{\circ}-\operatorname{cosec}^2 60^{\circ} = (\frac{\sqrt{3}}{2})^2+4\times1^2-(\frac{2}{\sqrt{3}})^2$ ⇒ $\sin ^2 60^{\circ}+4 \tan ^2 45^{\circ}-\operatorname{cosec}^2 60^{\circ} = \frac{3}{4}+4-\frac{4}{3}$ ⇒ $\sin ^2 60^{\circ}+4 \tan ^2 45^{\circ}-\operatorname{cosec}^2 60^{\circ} = \frac{41}{12}$ Computing LHS, $ \frac{k-k \cot ^2 30^{\circ}}{1+\cot ^2 30^{\circ}} = k(\frac{1- (\sqrt{3})^2}{1+(\sqrt{3})^2})$ ⇒ $ \frac{k-k \cot ^2 30^{\circ}}{1+\cot ^2 30^{\circ}} = \frac{-k}{2}$ So, $\frac{-k}{2}=\frac{41}{12}$ ⇒ $k=-6.83$ Hence, the correct answer is – 6.83.
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Question : If $x\sin ^{2}60^{\circ}-\frac{3}{2}\sec 60^{\circ}\tan^{2}30^{\circ}+\frac{4}{5}\sin ^{2}45^{\circ}\tan ^{2}60^{\circ}=0$, then $x$ is:
Option 1: $-\frac{1}{15}$
Option 2: $–4$
Option 3: $-\frac{4}{15}$
Option 4: $–2$
Question : The value of $\frac{4 \tan ^2 30^{\circ}+\sin ^2 30^{\circ} \cos ^2 45^{\circ}+\sec ^2 48^{\circ}-\cot ^2 42^{\circ}}{\cos 37^{\circ} \sin 53^{\circ}+\sin 37^{\circ} \cos 53^{\circ}+\tan 18^{\circ} \tan 72^{\circ}}$ is:
Option 1: $\frac{35}{48}$
Option 2: $\frac{59}{48}$
Option 3: $\frac{49}{24}$
Option 4: $\frac{35}{24}$
Question : The value of $\frac{3\left(\operatorname{cosec}^2 26^{\circ}-\tan ^2 64^{\circ}\right)+\left(\cot ^2 42^{\circ}-\sec ^2 48^{\circ}\right)}{\cot \left(22^{\circ}-\theta\right)-\operatorname{cosec}^2\left(62^{\circ}+\theta\right)-\tan \left(\theta+68^{\circ}\right)+\tan ^2\left(28^{\circ}-\theta\right)}$ is:
Option 1: 3
Option 2: 4
Option 3: –1
Option 4: –2
Question : If ${\operatorname{cosec} 39^{\circ}} = x$, then the value of $ \frac{1}{\operatorname{cosec}^2 51^{\circ}} +\sin^239^{\circ} +\tan ^251^{\circ} -\frac{1}{\sin ^2 51^{\circ} \sec ^2 39^{\circ}}$ is:
Option 1: $x^2-1$
Option 2: $\sqrt{x^2-1}$
Option 3: $ \sqrt{1-x^2}$
Option 4: $1-x^2$
Question : The value of $\frac{5 \cos ^2 60^{\circ}+4 \sec ^2 30^{\circ}-\tan ^2 45^{\circ}}{\tan ^2 60^{\circ}-\sin ^2 30^{\circ}-\cos ^2 45^{\circ}}$ is:
Option 1: $\frac{67}{27}$
Option 2: $\frac{22}{9}$
Option 3: $\frac{67}{24}$
Option 4: $\frac{19}{9}$
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