Question : If $\left ( a+\frac{1}{a} \right )^{2}=3$, then the value of $\left ( a^{2}+\frac{1}{a^{2}} \right )$ will be:
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: 3
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Correct Answer: 1
Solution : Given: $(a+\frac{1}{a})^2=3$ Expanding the left side of the equation: ⇒ $a^2 + 2(a)(\frac{1}{a}) + \left(\frac{1}{a}\right)^2 = 3$ ⇒ $a^2 + 2 + \frac{1}{a^2} = 3$ ⇒ $a^2 + \frac{1}{a^2} = 3 - 2$ ⇒ $a^2 + \frac{1}{a^2} = 1$ Therefore, the value of $a^2 + \frac{1}{a^2}$ is 1. Hence, the correct answer is 1.
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Question : If $\frac{1}{x^2+a^2}=x^2-a^2$, then the value of $x$ is:
Option 1: $\left(1-a^4\right)^\frac{1}{4}$
Option 2: $a$
Option 3: $\left(a^4-1\right)^\frac{1}{4}$
Option 4: $\left(a^4+1\right)^\frac{1}{4}$
Question : If $\left (a+\frac{1}{b} \right)=1$ and $\left (b+\frac{1}{c} \right)=1$, the value of $\left (c+\frac{1}{a} \right)$ is:
Option 3: – 1
Option 4: 2
Question : If $x^{2} -3x +1=0$, then the value of $\frac{\left(x^4+\frac{1}{x^2}\right)}{\left(x^2+5 x+1\right)}$ is:
Option 1: $\frac{9}{4}$
Option 2: $\frac{27}{8}$
Option 3: $\frac{5}{2}$
Option 4: $2$
Question : If $x+y+z=0$, then what is the value of $\frac{\left (3y^{2}+x^{2}+z^{2} \right )}{\left (2y^{2}-xz \right)}$?
Option 1: $2$
Option 2: $1$
Option 3: $\frac{3}{2}$
Option 4: $\frac{5}{3}$
Question : If $\left(\frac{\cos A}{1-\sin A}\right)+\left(\frac{\cos A}{1+\sin A}\right)=4$, then what will be the value of $A$? $\left(0^{\circ}<\theta<90^{\circ}\right)$
Option 1: $90^{\circ}$
Option 2: $45^{\circ}$
Option 3: $60^{\circ}$
Option 4: $30^{\circ}$
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