Question : If $\tan (11 \theta)=\cot (7 \theta)$, then what is the value of $\sin ^2(6 \theta)+\sec ^2(9 \theta)+\operatorname{cosec}^2(12 \theta) ?$
Option 1: $\frac{23}{6}$
Option 2: $\frac{35}{12}$
Option 3: $\frac{31}{12}$
Option 4: $\frac{43}{12}$
Correct Answer: $\frac{43}{12}$
Solution : $\tan (11 \theta)=\cot (7 \theta)$ $⇒\tan (11 \theta)=\tan (90^\circ-7 \theta)$ $⇒11 \theta=90^\circ-7 \theta$ $⇒18 \theta=90^\circ$ $⇒ \theta=5^\circ$ $\sin ^2(6 \theta)+\sec ^2(9 \theta)+\operatorname{cosec}^2(12 \theta)$ Substituting $ \theta=5^\circ$, $=\sin ^2(30 ^\circ)+\sec ^2(45 ^\circ)+\operatorname{cosec}^2(60 ^\circ)$ $=(\frac{1}{2})^2+(\sqrt2)^2+(\frac{2}{\sqrt3})^2$ $=\frac{1}{4}+2+\frac{4}{3}$ $=\frac{43}{12}$ Hence, the correct answer is $\frac{43}{12}$.
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Question : If $\frac{1}{\operatorname{cosec} \theta+1}+\frac{1}{\operatorname{cosec} \theta-1}=2 \sec \theta, 0^{\circ}<\theta<90^{\circ}$, then the value of $\frac{\tan \theta+2 \sec \theta}{\operatorname{cosec} \theta}$ is:
Option 1: $\frac{4+\sqrt{2}}{2}$
Option 2: $\frac{2+\sqrt{3}}{2}$
Option 3: $\frac{4+\sqrt{3}}{2}$
Option 4: $\frac{2+\sqrt{2}}{2}$
Question : The value of $\sqrt{\frac{1+\sin A}{1-\sin A}}$ is:
Option 1: $\sec A-\tan A$
Option 2: $\operatorname{cosec} A+\cot A$
Option 3: $\sec A+\tan A$
Option 4: $\operatorname{cosec} A-\cot A$
Question : If $7 \sin ^2 \theta+3 \cos ^2 \theta=4,0^{\circ}<\theta<90^{\circ}$, then the value of $(\tan ^2 2 \theta+\operatorname{cosec}^2 2 \theta)$ is:
Option 1: $7$
Option 2: $\frac{15}{4}$
Option 3: $\frac{13}{3}$
Option 4: $\frac{13}{4}$
Question : If $(\operatorname{cosec} \theta-\cot \theta) = \frac{7}{2}$, the value of $\operatorname{cosec} \theta$ is:
Option 1: $\frac{47}{28}$
Option 2: $\frac{51}{28}$
Option 3: $\frac{53}{28}$
Option 4: $\frac{49}{28}$
Question : If $\frac{\cos \theta}{1-\sin \theta}+\frac{\cos \theta}{1+\sin \theta}=4,0^{\circ}<\theta<90^{\circ}$, then what is the value of $(\sec \theta+\operatorname{cosec} \theta+\cot \theta) ?$
Option 1: $1+2 \sqrt{3}$
Option 2: $\frac{1+2 \sqrt{3}}{3}$
Option 3: $\frac{2+\sqrt{3}}{3}$
Option 4: $2+\sqrt{3}$
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