Question : If $p-\frac{1}{p}=6$, then what is the value of $p^4+\frac{1}{p^4}$?
Option 1: 1562
Option 2: 1432
Option 3: 1442
Option 4: 1444
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Correct Answer: 1442
Solution : $\mathrm{p}-\frac{1}{\mathrm{p}}=6$ Squaring both sides, we get, $⇒p^2+\frac{1}{p^2}-2(p)(\frac{1}{p})=36$ $⇒p^2+\frac{1}{p^2}-2=36$ $⇒p^2+\frac{1}{p^2}=38$ Squaring both sides again, we get, $⇒p^4+\frac{1}{p^4}+2(p^2)(\frac{1}{p^2})=1444$ $⇒p^4+\frac{1}{p^4}+2=1444$ $\therefore p^4+\frac{1}{p^4}=1442$ Hence, the correct answer is 1442.
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Question : The value of $4 \div 12$ of $[3 \div 4$ of $\{(4-2) \times 6 \div 2\}]-2 \times 6 \div 8+3$ is:
Option 1: $4 \frac{1}{6}$
Option 2: $3 \frac{1}{3}$
Option 3: $2 \frac{1}{3}$
Option 4: $7 \frac{1}{6}$
Question : If $x-\frac{1}{x}=2$, then what is the value of $x^2+\frac{1}{x^2}$?
Option 1: 4
Option 2: 5
Option 3: 3
Option 4: 6
Question : If $2x+\frac{1}{3x}$ = 5, then the value of $\frac{5x}{6x^{2}+20x+1}$ is:
Option 1: $\frac{1}{4}$
Option 2: $\frac{1}{6}$
Option 3: $\frac{1}{5}$
Option 4: $\frac{1}{7}$
Question : If $x+\frac{1}{x}=5$, then the value of $\frac{x}{1+x+x^2}$ is:
Option 1: $\frac{1}{5}$
Option 3: $5$
Option 4: $6$
Question : If $\frac{1}{6}$ of $x$ – $\frac{7}{2}$ of $\frac{3}{7}$ equals to $(-\frac{7}{4})$, then the value of $x$ is:
Option 1: –1.5
Option 2: –3
Option 3: –2.5
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