Question : If $\cos \theta+\sin \theta=\sqrt{2}$, then what is the value of $\sec \theta \operatorname{cosec} \theta$ ?
Option 1: $\frac{1}{2}$
Option 2: $1$
Option 3: $2$
Option 4: $0$
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Correct Answer: $2$
Solution : Given: $\cos \theta+\sin \theta=\sqrt{2}$ Squaring both sides, we get: ⇒ $(\cos \theta+\sin \theta)^2=(\sqrt{2})^2$ ⇒ $\cos^2 \theta+\sin^2 \theta+2\sin\theta \cos\theta=2$ We know that $\cos^2 \theta+\sin^2 \theta = 1$ Thus, $1+2\sin\theta \cos\theta=2$ ⇒ $2\sin\theta \cos\theta=2-1$ ⇒ $\sin\theta \cos\theta=\frac{1}{2}$ ⇒ $\frac{1}{\operatorname{cosec}\theta}\frac{1}{\sec\theta}=\frac{1}{2}$ ⇒ $\operatorname{cosec}\theta \sec\theta = 2$ Hence, the correct answer is $2$.
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Question : If $\frac{\sin \theta-\cos \theta}{\sin \theta+\cos \theta}=\frac{4}{5}$, then the value of $\frac{\operatorname{cosec}^2 \theta}{2-\operatorname{cosec}^2 \theta}$ is:
Option 1: $\frac{16}{25}$
Option 2: $\frac{40}{41}$
Option 3: $\frac{41}{40}$
Option 4: $\frac{31}{30}$
Question : If $\sin \theta+\cos \theta=\frac{1}{29}$, then find the value of $\frac{\operatorname{sin} \theta+\operatorname{cos} \theta}{\operatorname{sin} \theta-\operatorname{cos} \theta}$.
Option 1: $\frac{1}{41}$
Option 2: $\frac{43}{29}$
Option 3: $\frac{41}{29}$
Option 4: $\frac{1}{43}$
Question : If $\cos \theta+\sec \theta=\sqrt{3}$, then the value of $\cos ^3 \theta+\sec ^3 \theta$ is:
Option 1: $0$
Option 2: $\frac{1}{\sqrt{3}}$
Option 3: $\sqrt{3}$
Option 4: $2 \sqrt{3}$
Question : What is the value of $\sqrt{\frac{\operatorname{cosec} A+1}{\operatorname{cosec} A-1}}+\sqrt{\frac{\operatorname{cosec} A-1}{\operatorname{cosec} A+1}}$?
Option 1: $2 \cos A$
Option 2: $\sec A$
Option 3: $2\cos A$
Option 4: $2 \sec A$
Question : If $-\sin \theta+\operatorname{cosec} \theta=6$, then what is the value of $\sin \theta+\operatorname{cosec} \theta$ ?
Option 1: $6$
Option 2: $\sqrt{40}$
Option 3: $\sqrt{34}$
Option 4: $\sqrt{38}$
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