Question : If $\cot 2 {A}=\tan \left({A}-48^{\circ}\right)$, then what is the value of $A$?
Option 1: $36^{\circ}$
Option 2: $46^{\circ}$
Option 3: $42^{\circ}$
Option 4: $40^{\circ}$
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Correct Answer: $46^{\circ}$
Solution : $\cot 2 {A}=\tan \left({A}-48^{\circ}\right)$ $⇒\tan(90^{\circ}- 2 {A})=\tan \left({A}-48^{\circ}\right)$ $⇒90^{\circ}- 2 {A}=A-48^{\circ}$ $⇒3 {A}= 138^{\circ}$ $\therefore {A}= 46^{\circ}$ Hence, the correct answer is $46^{\circ}$.
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Question : What is the value of $\left(\tan 10^{\circ} \tan 80^{\circ}+\tan 20^{\circ} \tan 70^{\circ}+\tan 30^{\circ} \tan 60^{\circ}+\tan 40^{\circ} \tan 50^{\circ}\right)$?
Option 1: 4
Option 2: 3
Option 3: 5
Option 4: 2
Question : If $\tan 2 \theta=\cot \left(\theta-36^{\circ}\right)$, where $2 \theta$ is an acute angle, then the value of $\theta$ is:
Option 1: 18°
Option 2: 36°
Option 3: 30°
Option 4: 42°
Question : Evaluate the given expression: $\cos ^2 36^{\circ}+\cos 54^{\circ} \cdot \sin 36^{\circ}+\left(\frac{\tan 26^{\circ}}{\cot 64^{\circ}}\right)$
Option 3: 1
Question : If $\cot 3 \mathrm{~A}=\tan \left(\mathrm{A}-36^{\circ}\right)$, then what is the value of $\mathrm{A}$?
Option 1: 33.5 degrees
Option 2: 25 degrees
Option 3: 30 degrees
Option 4: 31.5 degrees
Question : If $\mathrm{A}=\cot 30^{\circ} \tan 60^{\circ}+\cot 60^{\circ} \tan 30^{\circ}$, then what is the value of A?
Option 1: $\frac{1}{ \sqrt{ 3}}$
Option 2: $\frac{10}{3}$
Option 3: $\frac{10}{ \sqrt{3}}$
Option 4: $\frac{1}{3}$
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