Question : If $x^2-15 x+1=0$, what is the value of $x^4-223 x^2+6 ?$
Option 1: 9
Option 2: 5
Option 3: 6
Option 4: 0
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Correct Answer: 5
Solution : $x^2-15 x+1=0$ $⇒x^2+1=15 x$ $⇒(x^2+1)^{2}= (15x)^{2}$ $⇒x^4+2x^2+1= 225x^2$ $⇒x^4-223x^2 = –1$ Adding 6 on both sides, we get, So, $x^4-223 x^2+6 = –1+6 = 5$ Hence, the correct answer is 5.
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Question : If $2 x^2-7 x+5=0$, then what is the value of $x^2+\frac{25}{4 x^2} ?$
Option 1: $5 \frac{1}{2}$
Option 2: $7 \frac{1}{4}$
Option 3: $9 \frac{1}{2}$
Option 4: $9 \frac{3}{4}$
Question : If $x-\frac{1}{x}=5, x \neq 0$, then what is the value of $\frac{x^6+3 x^3-1}{x^6-8 x^3-1} ?$
Option 1: $\frac{3}{8}$
Option 2: $\frac{13}{12}$
Option 3: $\frac{4}{9}$
Option 4: $\frac{11}{13}$
Question : If $x+\frac{1}{x}=1$, then the value of $x^{12}+x^9+x^6+x^3+1$ is:
Option 1: 1
Option 2: - 1
Option 3: 0
Option 4: - 2
Question : If $x^2-5 x+1=0$, then the value of $\frac{x^6+x^4+x^2+1}{5 x^3}=?$
Option 1: 30
Option 2: 25
Option 3: 23
Option 4: 28
Question : If $(x+\frac{1}{x})\neq 0$ and $(x^3+\frac{1}{x^3})= 0$, then the value $(x+\frac{1}{x})^4$ is:
Option 2: 12
Option 3: 15
Option 4: 16
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