Question : If $\tan^4\theta + \tan^2\theta=1$, what is the value of $11(\cos^4\theta+\cos^2\theta)$?
Option 1: – 11
Option 2: 8
Option 3: 0
Option 4: 11
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Correct Answer: 11
Solution : Given: $\tan^4\theta + \tan^2\theta=1$ ⇒ $\tan^2\theta(\tan^2\theta+1)=1 [\because \sec^2\theta-\tan^2\theta=1]$ ⇒ $\tan^2\theta \sec^2\theta=1$ $\therefore \tan^2\theta=\cos^2\theta$ $11(\cos^4\theta+\cos^2\theta)$ = $11[(\cos^2\theta)^2+\cos^2\theta]$ = $11(\tan^4\theta + \tan^2\theta)$ = $11×1$ = $11$ Hence, the correct answer is 11.
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Question : If $\tan\theta=1$, then the value of $\frac{8\sin\theta\:+\:5\cos\theta}{\sin^{3}\theta\:–\:2\cos^{3}\theta\:+\:7\cos\theta}$ is:
Option 1: $2$
Option 2: $2\frac{1}{2}$
Option 3: $3$
Option 4: $\frac{4}{5}$
Question : If $\tan \theta=\frac{4}{3}$, then the value of $\frac{3\sin \theta+ 2\cos \theta}{3\sin \theta – 2 \cos \theta}$ is:
Option 1: $\frac{1}{2}$
Option 2: $1\frac{1}{2}$
Option 4: $–3$
Question : If $\sin\theta+\sin^{2}\theta=1$, then the value of $\cos^{12}\theta+3\cos^{10}\theta+3\cos^{8}\theta+\cos^{6}\theta-1$ is:
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 0
Question : If $2 \cot \theta = 3$, find the value of $\frac{\sqrt{13} \sin \theta – 3 \tan \theta}{3 \tan \theta + \sqrt{13} \cos \theta}$
Option 1: $\frac{1}{\sqrt{13}}$
Option 2: $\frac{2}{\sqrt{13}}$
Option 4: $\frac{2}{3}$
Question : If $\sin \theta=\frac{1}{2}$, then the value of $\left(3 \cos \theta-4 \cos ^3 \theta\right)$ is:
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: – 1
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