Question : If $x-\frac{1}{x}=-6$, what will be the value of $x^5-\frac{1}{x^5}?$
Option 1: –8898
Option 2: –8896
Option 3: –8886
Option 4: –8892
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Correct Answer: –8886
Solution : Given: $x-\frac{1}{x}=-6$ ----------------(equation1) Squaring both sides of equation 1, we get: ⇒ $x^2+\frac{1}{x^2}-2=(-6)^2$ ⇒ $x^2+\frac{1}{x^2}=38$ Cubing both sides of equation 1, we get: ⇒ $x^3-\frac{1}{x^3}-3×x×\frac{1}{x}(x-\frac{1}{x})=(-6)^3$ ⇒ $x^3-\frac{1}{x^3}=-216+3×(-6)$ ⇒ $x^3-\frac{1}{x^3}=-234$ Now, $(x^2+\frac{1}{x^2})(x^3-\frac{1}{x^3})=38×(-234)$ ⇒ $(x^5-\frac{1}{x^5})+(x-\frac{1}{x})=(-8892)$ ⇒ $(x^5-\frac{1}{x^5})+(-6)=(-8892)$ $\therefore(x^5-\frac{1}{x^5})= -8886$ Hence, the correct answer is –8886.
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Question : If $x+\frac{1}{x}=-6$, what will be the value of $x^5+\frac{1}{x^5}$?
Option 1: – 7776
Option 2: – 6726
Option 3: – 6738
Option 4: – 6732
Question : If $(-\frac{1}{2}) \times (x-5) + 3 = -\frac{5}{2}$, then what is the value of $x$?
Option 1: 16
Option 2: 4
Option 3: – 6
Option 4: – 4
Question : If $(x+\frac{1}{x})^2=3$, then what is the value of $x^6 + x^{–6}$?
Option 1: 6
Option 2: 2
Option 3: –6
Option 4: –2
Question : If $x+\frac{1}{x}=5$, then the value of $\frac{x}{1+x+x^2}$ is:
Option 1: $\frac{1}{5}$
Option 2: $\frac{1}{6}$
Option 3: $5$
Option 4: $6$
Question : If $x+5+\frac{1}{x+1}=6$, then the value of $(x+1)^{3}+\frac{1}{(x+1)^{3}}$ is:
Option 1: 2
Option 2: 0
Option 3: –2
Option 4: 4
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