Question : In a right triangle for an acute angle $x$, if $\sin x=\frac{3}{7}$, then find the value of $\cos x$.
Option 1: $\frac{2}{7}$
Option 2: $\frac{3}{4}$
Option 3: $\frac{1}{\sqrt{3}}$
Option 4: $\frac{2\sqrt{10}}{7}$
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Correct Answer: $\frac{2\sqrt{10}}{7}$
Solution : Given that, it is a right-angle triangle with an acute angle $x$. $\therefore$ Angle $x$ lies between $0$ to $\frac{\pi}{2}$ Given: $\sin x=\frac{3}{7}$ Squaring both sides, $\sin^2 x=\frac{9}{49}$ Since $\sin^2 x+ \cos^2 x=1$, So, $\cos^2 x=1-\frac{9}{49}$ ⇒ $\cos x =\frac{2\sqrt {10}}{7}$ Hence, the correct answer is $\frac{2\sqrt{10}}{7}$.
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Question : In $\triangle{XYZ}$, right-angled at $Y$, if $\sin X = \frac{1}{2}$, find the value of $\cos X \cos Z + \sin X \sin Z$.
Option 1: $\frac{\sqrt{3}}{2}$
Option 2: $\frac{\sqrt{3}}{4}$
Option 3: $\frac{2}{\sqrt{3}}$
Option 4: $\sqrt{3}$
Question : If $\tan \frac{A}{2}=x$, then find $x$.
Option 1: $\frac{\sqrt{1+\cos A}}{\sqrt{1-\cos A}}$
Option 2: $\frac{\sqrt{1-\sin A}}{\sqrt{1+\cos A}}$
Option 3: $\frac{\sqrt{1-\cos A}}{\sqrt{1+\cos A}}$
Option 4: $\frac{\sqrt{\cos A-1}}{\sqrt{1+\cos A}}$
Question : $\triangle ABC$ is a right triangle. If $\angle B=90^{\circ}$ and $\tan A=\frac{1}{\sqrt{2}}$, then the value of $\sin A \cos C + \cos A \sin C$ is:
Option 1: $1$
Option 2: $2$
Option 3: $\frac{2}{3}$
Option 4: $\frac{1}{3}$
Question : If $\cos^2 \theta=\frac{3}{4}$, where $\theta$ is an acute angle, then the value of $\sin \left(\theta+30^{\circ}\right)$ is:
Option 2: $\frac{1}{\sqrt{2}}$
Option 3: $\frac{1}{2}$
Option 4: $\frac{\sqrt{3}}{2}$
Question : If $\cos x+\sin x=\sqrt{2} \cos x$, what is the value of $(\cos x-\sin x)^2+(\cos x+\sin x)^2$?
Option 1: $2$
Option 2: $1$
Option 3: $0$
Option 4: $\frac{1}{\sqrt{2}}$
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