Question : In a triangle ABC, $\angle$BAC = 90°. If BC = 25 cm, then what is the length of the median AD?
Option 1: 10 cm
Option 2: 12.5 cm
Option 3: 14.5 cm
Option 4: 24 cm
Correct Answer: 12.5 cm
Solution : Given: $\Delta ABC$ is a right triangle and BC is the hypotenuse. BC = 25 cm we know that $\text{Median of right triangle} =\ \frac{\text{Hypotenuse}}{2}$ $=\ \frac{BC}{2}$ $=\ \frac{25}{2}$ $=\ 12.5$ cm Hence the length of the median is 12.5 cm.
Application | Eligibility | Selection Process | Result | Cutoff | Admit Card | Preparation Tips
Question : In $\triangle$ ABC, $\angle$ BCA = $90^{\circ}$, AC = 24 cm and BC = 10 cm. What is the radius (in cm) of the circumcircle of $\triangle$ ABC?
Option 1: 12.5
Option 2: 13
Option 3: 25
Option 4: 26
Question : In $\triangle$ABC, D is the median from A to BC. AB = 6 cm, AC = 8 cm, and BC = 10 cm.The length of median AD (in cm) is:
Option 1: 4.5
Option 2: 5
Option 3: 4
Option 4: 3
Question : $\triangle \mathrm{ABC}$ and $\triangle \mathrm{DEF}$ are two triangles such that $\triangle \mathrm{ABC} \cong \triangle \mathrm{FDE}$. If AB = 5 cm, $\angle$B = 40° and $\angle$A = 80°, then which of the following options is true?
Option 1: DF = 5 cm, $\angle$E = 60°
Option 2: DE = 5 cm, $\angle$F = 60°
Option 3: DE = 5 cm, $\angle$D = 60°
Option 4: DE = 5 cm, $\angle$E = 60°
Question : In a $\triangle ABC$, the bisectors of $\angle$ABC and $\angle$ACB intersect each other at point O. If the $\angle$BOC is 125°, then the $\angle$BAC is equal to:
Option 1: 75°
Option 2: 78°
Option 3: 70°
Option 4: 82°
Question : If two medians BE and CF of a triangle ABC, intersect each other at G and if BG = CG, $\angle$BGC = $120^{\circ}$, BC = 10 cm, then the area of the triangle ABC is:
Option 1: $50\sqrt{3}$ $cm^2$
Option 2: $60$ $cm^2$
Option 3: $25$ $cm^2$
Option 4: $25\sqrt{3}$ $cm^2$
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile