Question : In $\triangle$ABC, $\angle$A = $\angle$B = 60°, AC = $\sqrt{13}$ cm, the lines AD and BD intersect at D with $\angle$D = 90°. If DB = 2 cm, then the length of AD is:
Option 1: 3 cm
Option 2: 3.5 cm
Option 3: 4 cm
Option 4: 4.7 cm
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Correct Answer: 3 cm
Solution : $\angle$C = 180° – 60° – 60° = 60° So, it is an equilateral triangle. $\therefore$ AB = BC = AC = $\sqrt{13}$ cm In $\triangle$ADB, AB2 = AD2 + DB2 ⇒ AD = $\sqrt{(\sqrt{13})^2-2^2}=\sqrt{9}=3$ cm Hence, the correct answer is 3 cm.
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Question : $\angle A$ of $\triangle ABC$ is a right angle. $AD$ is perpendicular on $BC$. If $BC= 14$ cm and $BD= 5$ cm, then measure of $AD$ is:
Option 1: $2\sqrt5$ cm
Option 2: $\sqrt5$ cm
Option 3: $3\sqrt5$ cm
Option 4: $3.5\sqrt5$ cm
Question : In $\triangle $ABC, AD$\perp$ BC and AD2 = BD × DC. The measure of $\angle$ BAC is:
Option 1: 60°
Option 2: 75°
Option 3: 90°
Option 4: 45°
Question : In a triangle the length of the opposite side of the angle which measures 45° is 8 cm, what is the length of the side opposite to the angle which measures 90°?
Option 1: $8\sqrt{2}$ cm
Option 2: $4\sqrt{2}$ cm
Option 3: $8\sqrt{3}$ cm
Option 4: $4\sqrt{3}$ cm
Question : $\triangle \mathrm{ABC}$ is an isosceles triangle with $\angle \mathrm{ABC}=90^{\circ}$ and $\mathrm{AB}=\mathrm{BC}$. If $\mathrm{AC}=12 \mathrm{~cm}$, then the length of $\mathrm{BC}$ (in $\mathrm{cm}$) is equal to:
Option 1: $6 \sqrt{2}$
Option 2: $8$
Option 3: $6$
Option 4: $8 \sqrt{2}$
Question : In triangle ABC, $\angle$ABC = 15°. D is a point on BC such that AD = BD. What is the measure of $\angle$ADC (in degrees)?
Option 1: 15
Option 2: 30
Option 3: 45
Option 4: 60
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