Question : In $\triangle$ ABC, $\angle$ BCA = $90^{\circ}$, AC = 24 cm and BC = 10 cm. What is the radius (in cm) of the circumcircle of $\triangle$ ABC?
Option 1: 12.5
Option 2: 13
Option 3: 25
Option 4: 26
Correct Answer: 13
Solution : In $\triangle$ ABC, $\angle$ BCA = $90^{\circ}$, AC = 24 cm and BC = 10 cm AB2 = AC2 + BC2 $AB = \sqrt{24^2 + 10^2} = \sqrt{576+100} = \sqrt{676} = 26$ cm Circumradius of $\triangle ABC = \frac{AB}{2} = \frac{26}{2} = 13$ cm Hence, the correct answer is 13.
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Question : In $\triangle$PQR, $\angle$ PQR = $90^{\circ}$, PQ = 5 cm and QR = 12 cm. What is the radius (in cm) of the circumcircle of $\triangle$PQR?
Option 1: 6.5
Option 2: 7.5
Option 3: 13
Option 4: 15
Question : In a triangle ABC, $\angle$BAC = 90°. If BC = 25 cm, then what is the length of the median AD?
Option 1: 10 cm
Option 2: 12.5 cm
Option 3: 14.5 cm
Option 4: 24 cm
Question : If AB = 5 cm, AC = 12 cm, and AB$\perp$ AC, then the radius of the circumcircle of $\triangle ABC$ is:
Option 1: 6.5 cm
Option 2: 6 cm
Option 3: 5 cm
Option 4: 7 cm
Question : In a triangle ABC, if $\angle B=90^{\circ}, \angle C=45^{\circ}$ and AC = 4 cm, then the value of BC is:
Option 1: $\sqrt{2} \mathrm{~cm}$
Option 2: $4 \mathrm{~cm}$
Option 3: $2 \sqrt{2} \mathrm{~cm}$
Option 4: $4 \sqrt{2} \mathrm{~cm}$
Question : In $\triangle{ABC}, \angle A=90^{\circ}, {AB}=16\ cm $ and $AC =12 \ cm$. $D$ is the midpoint of $AC$ and $DE \perp CB$ at $E$. What is the area (in ${cm}^2$ ) of $\triangle{CDE}$?
Option 1: 8.64
Option 2: 7.68
Option 3: 5.76
Option 4: 6.25
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