Question : In an equilateral triangle inradius is 4 cm. What is the circumradius?
Option 1: 6 cm
Option 2: 8 cm
Option 3: 12 cm
Option 4: 2 cm
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Correct Answer: 8 cm
Solution : The circumradius $(R)$ and inradius $(r)$ are related by the formula: $ R = \frac{a}{\sqrt{3}}$ and $ r = \frac{a}{2\sqrt{3}}$ Where $a$ is the side of the triangle Given: Inradius = 4 cm, we can find the side of the triangle: $ a = 2\sqrt{3} \times r = 2\sqrt{3} \times 4 = 8\sqrt{3}\ \text{cm}$ Substituting $a$ into the formula for the circumradius, we get: $ R = \frac{a}{\sqrt{3}} = \frac{8\sqrt{3}}{\sqrt{3}} = 8 \ \text{cm}$ Hence, the correct answer is 8 cm.
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Question : The inradius of an equilateral triangle is $\sqrt3$ cm, then the perimeter of that triangle is:
Option 1: 18 cm
Option 2: 15 cm
Option 4: 6 cm
Question : An equilateral triangle has sides of 18 cm each. The ratio of the inradius to circumradius of the triangle is:
Option 1: 2 : 1
Option 2: 3 : 2
Option 3: 3 : 4
Option 4: 1 : 2
Question : In an equilateral triangle STU, inradius is $5 \sqrt{3 }\mathrm{~cm}$. What is the length of the side of this equilateral triangle?
Option 1: $20 \sqrt{3} \mathrm{~cm}$
Option 2: $18 \sqrt{3} \mathrm{~cm}$
Option 3: $30 \mathrm{~cm}$
Option 4: $24 \mathrm{~cm}$
Question : In an equilateral triangle, the circumradius is 14 cm. What is the length of the median in this triangle?
Option 1: $14 \sqrt{3} \mathrm{~cm}$
Option 2: $21 \mathrm{~cm}$
Option 3: $18 \sqrt{3} \mathrm{~cm}$
Option 4: $7 \sqrt{3} \mathrm{~cm}$
Question : If the height of the equilateral triangle is $2 \sqrt 3\:\operatorname{cm}$, then determine the area of the equilateral triangle.
Option 1: $6\:\operatorname{cm^2}$
Option 2: $2\sqrt3\:\operatorname{cm^2}$
Option 3: $4\sqrt3\:\operatorname{cm^2}$
Option 4: $12\:\operatorname{cm^2}$
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