Question : In $\triangle ABC, \angle A+\angle B=145^{\circ}$ and $\angle C+2\angle B=180^{\circ}$. State which one of the following relations is true.
Option 1: CA = AB
Option 2: CA < AB
Option 3: BC > AB
Option 4: CA > AB
Correct Answer: CA > AB
Solution : In $\triangle$ABC, $\angle$ A + $\angle$ B + $\angle$ C = 180° [Angle sum property of a triangle] _____(1) $\angle$ A + $\angle$ B = 135° _____(2) $\angle$ C + 2$\angle$ B = 180° _____(3) From equation (1) and (3) $\angle$ A + $\angle$ B + $\angle$ C = $\angle$ C + 2$\angle$ B ⇒ $\angle$ A = $\angle$ B = 67.5° (since $\angle$ A + $\angle$ B = 135°) ⇒ $\angle$ C = 180° – 135° = 45° ⇒ $\angle$B > $\angle$C ⇒ CA > AB Hence, the correct answer is CA > AB.
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Question : Internal bisectors of $\angle$ B and $\angle$ C of $\triangle$ ABC meet at O. If $\angle$ BAC = $80^{\circ}$, then the value of $\angle$ BOC is:
Option 1: $120^{\circ}$
Option 2: $140^{\circ}$
Option 3: $110^{\circ}$
Option 4: $130^{\circ}$
Question : 'I' is the incentre of $\triangle$ABC. If $\angle$BIC = 108$^\circ$, then $\angle$A = ?
Option 1: 54$^\circ$
Option 2: 36$^\circ$
Option 3: 72$^\circ$
Option 4: 81$^\circ$
Question : In $\triangle$ABC, $\angle$A = 66°. AB and AC are produced at points D and E, respectively. If the bisectors of $\angle$CBD and $\angle$BCE meet at the point O, then $\angle$BOC is equal to:
Option 1: $66^{\circ}$
Option 2: $93^{\circ}$
Option 3: $57^{\circ}$
Option 4: $114^{\circ}$
Question : In a $\triangle \mathrm{ABC}$, the bisectors of $\angle \mathrm{B}$ and $\angle \mathrm{C}$ meet at $\mathrm{O}$. If $\angle \mathrm{BOC}=142^{\circ}$, then the measure of $\angle \mathrm{A}$ is:
Option 1: $52^\circ$
Option 2: $68^\circ$
Option 3: $104^\circ$
Option 4: $116^\circ$
Question : In a triangle, ABC, BC is produced to D so that CD = AC. If $\angle BAD=111^{\circ}$ and $\angle ACB=80^{\circ}$, then the measure of $\angle ABC$ is:
Option 1: 31°
Option 2: 33°
Option 3: 35°
Option 4: 29°
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