in jee main I got 33.5673 percentile (OBC) , is able to get nit college?

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in jee main I got 33.5673 percentile (OBC) , is able to get nit college?

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shyamkumar53877 12th Sep, 2020

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NILUTPOL Student Expert 12th Sep, 2020

Hello,
With around 33 percentile in JEE Mains, you have not cleared the cutoffs for JEE Mains 2020. Even your rank in the common rank list would be more than 5.5 lakh. Even your category rank would be too high.
With that huge rank,you have no chances of getting a seat in any government engineering colleges like NITs IIITs and GFTIs. You are not eligible to appear JEE Advanced.

Please go for aoem top private engineering colleges in India which conduct their own entrance exams which are very easy as compared to JEE Mains.
Some of them are

Sharda University Greater Noida
Amity University Noida
SRM University Chennai
LPU Jalandhar

Please visit this link for a list of top private engineering colleges in India

hope it helps

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Shoaib Akhtar 12th Sep, 2020

hello shyam

well i don't think so that you can get into any NITs at this percentile .you can try looking some private colleges taking admissions on the basis of jee mains . you can also check the colleges you can get using the college predictor

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

best wishes

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ARYAN SAGAR 12th Sep, 2020

Sorry candidate,
With this much percentile score you have not cleared this year jee mains cutoff set by nta in obc category.
This year the qualifying cutoff for obc ncl category was around 70 percentile. And your score is very low as considered compared to this cut off score.
So you have not cleared the cutoff of jee mains 2020 of obc category. And you will not get any nit college. You may try at some other state colleges or some other private institutions. Or you can prepare one again and give the exam next year with full confidence.
On the basis of your rank your can check out college prediction tool given in the link below :-

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

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