Hello Tanika

Congrats for scoring 94 percentile in JEE main paper 2.

We can't say that what NIT you wil get but we can predict the rank with this percentile .

There is a pedicted formula from our team to predict rank

Total No of students = 145386

Formula

Probable Rank= ( 100 - your NTA percentile ) x 145386 / 100

So your predicted rank  =8723 approx

Our Team predicted that the qualify cutt off would be above 85 percentile .But it just a prediction .So pleae wait till april.

Hello Aspirant.

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As per previous years trends you may have chance to get nit Raipur and nit hamirpur.but this year it is difficult to predict because the exam held twice and the aspirants may increase their scores by second jEE mains exam which was held on April.better to give attempt to April jEE mains exam because if you get 95+ percentile score in this April exam then you have more chances to get top Nits.

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Use this formula to predict the rank:

• Rank Formula = (100 - your total score) X 145386 /100.
• Your expected rank is 8723 by using above formula.

Your rank may differ from the official cutoff and results which were released on the month of April by national testing agency NTA officially.

You have to wait for the official results.if you want to compare with previous years cutoff of b.arch .you can go through the below link:

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https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

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If you have any questions further let me know.

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Thank you!!!

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