Question : In the given figure, ABCD is a square of side 14 cm. E and F are mid-points of sides AB and DC respectively. EPF is a semi-circle whose diameter is EF. LMNO is square. What is the area (in cm2) of the shaded region?
Option 1: 108.5
Option 2: 94.5
Option 3: 70
Option 4: 120
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Correct Answer: 94.5
Solution : Given that ABCD is a square of side 14 cm. The area of the semicircle = $\frac{\pi r^2}{2}$ = $\frac{\pi (7)^2}{2}$ = 77 cm2 Since the radius of the semicircle is equal to the diagonal of a smaller square. The diagonal of a square = 7 cm The side of a smaller square = $\frac{7}{\sqrt2}$ cm The area of a smaller square = $\frac{49}{2}$ cm2 The area of a bigger square = 142 = 196 cm2 The area of the shaded region = The area of a bigger square – The area of a smaller square – The area of the semicircle The area of the shaded region = 196 – 77 – $\frac{49}{2}$ = 94.5 cm2 Hence, the correct answer is 94.5.
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Question : In the given figure, ABCD is a square. EFGH is a square formed by joining mid-points of sides of ABCD. LMNO is a square formed by joining mid-points of sides of EFGH. A circle is inscribed inside LMNO. If the area of a circle is 38.5 cm2 then what is the area (in cm2) of square ABCD?
Option 1: 98
Option 2: 196
Option 3: 122.5
Option 4: 171.5
Question : In a trapezium ABCD, AB and DC are parallel sides and $\angle ADC=90^\circ$. If AB = 15 cm, CD = 40 cm and diagonal AC = 41 cm, then the area of the trapezium ABCD is:
Option 1: 245 cm2
Option 2: 240 cm2
Option 3: 247.5 cm2
Option 4: 250 cm2
Question : Let A, B, and C be the mid-points of sides PQ, QR, and PR, respectively, of PQR. If the area of $\triangle$ PQR is 32 cm2, then find the area of $\triangle$ ABC.
Option 1: 24 cm2
Option 2: 16 cm2
Option 3: 32 cm2
Option 4: 8 cm2
Question : If the diameter of a sphere is 3.5 cm, then what is the total surface area of the sphere?
Option 1: 45.75 cm2
Option 2: 42.6 cm2
Option 3: 38.5 cm2
Option 4: 34.25 cm2
Question : The base of a right pyramid is square of side 10 cm. If the height of the pyramid is 12 cm, then its total surface area is:
Option 1: 400 cm2
Option 2: 460 cm2
Option 3: 260 cm2
Option 4: 360 cm2
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