Integral (sin x) (cos x) dx
Let u = cos x
Then du = -sin x
Integral -u du = -u²/2 + C, where C is the constant of integration.
Integral -u du = -cos²x/2 + C
Putting limit from 0 to 90:
cos 90 = 0
cos 0 = 1
=> -cos²(90)/2+C - {-cos²(0)/2+C}
=> -0+C - {-1/2+C}
=> -0+C + 1/2-C
=> 1/2
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